The area of a kite (or any quadrilateral having diagonals that cross at right angles) is half the product of the lenghts of the diagonals.
A = (1/2)(5 m +5 m)(3m +8 m)
A = 55 m²
The area of the figure is 55 m².
32/8=4
4x9=36
36 students total
X=1 -> y= -1/4
x=2 -> y= -2/3
x=3 -> y= -11/4
Answer:
Expresion:
![\frac{2}{5}(\frac{5}{6}*42)](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%28%5Cfrac%7B5%7D%7B6%7D%2A42%29)
Evaluating:
![\frac{2}{5}(\frac{5*42}{6})=\frac{2}{5}(\frac{210}{6})=\frac{2*210}{5*6}=\frac{420}{30}=14](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%28%5Cfrac%7B5%2A42%7D%7B6%7D%29%3D%5Cfrac%7B2%7D%7B5%7D%28%5Cfrac%7B210%7D%7B6%7D%29%3D%5Cfrac%7B2%2A210%7D%7B5%2A6%7D%3D%5Cfrac%7B420%7D%7B30%7D%3D14)
Step-by-step explanation:
By definition, a product is the result of a multiplication. For example:
![a*b=c](https://tex.z-dn.net/?f=a%2Ab%3Dc)
In this example "a" and "b" are the factors and "c" is the product.
Therefore, given:
"
of the product
and
"
You can observe that it indicates that the result obtained by multiplying
and
, is multiplied by
.
Knowing this, you can write the following expression:
![\frac{2}{5}(\frac{5}{6}*42)](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%28%5Cfrac%7B5%7D%7B6%7D%2A42%29)
Finally, evaluating, you get this result:
![\frac{2}{5}(\frac{5*42}{6})=\frac{2}{5}(\frac{210}{6})=\frac{2*210}{5*6}=\frac{420}{30}=14](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B5%7D%28%5Cfrac%7B5%2A42%7D%7B6%7D%29%3D%5Cfrac%7B2%7D%7B5%7D%28%5Cfrac%7B210%7D%7B6%7D%29%3D%5Cfrac%7B2%2A210%7D%7B5%2A6%7D%3D%5Cfrac%7B420%7D%7B30%7D%3D14)
Answer:
68/5 is already in the simplest form. It can be written as 13.6 in decimal form (rounded to 6 decimal places)