2 years ago

2 tables and 3 chairs together cost $1900 wher93 tables and 2 chairs together cost $2600. Find the cost of a table and a chair.

Mathematics

1 answer:

valentina_108 [34]2 years ago

6 0

Answer:

you can solve all your problems posted by this method ...

Step-by-step explanation:

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KonstantinChe [14]

Answer:

b = -6

Step-by-step explanation:

Apply the exponent rule that $\frac{1}{x^{n}} = x^{-n}$

In this case, $\frac{1}{y^{24}} = y^{-24}$

Set that equal to $(y^{b})^{4}$ :

$(y^{b})^{4} = y^{-24}$

Apply the exponent rule that $(x^{m})^{n} = x^{mn}$ so now you get:

$y^{4b} = y^{-24}$

Since the base is y for both sides of the equation, just set the exponents equal to each other and solve for b.

4b = -24

divide each side by 4 to get:

b = -6

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2 tables and 3 chairs together cost $1900 wher93 tables and 2 chairs together cost $2600. Find the cost of a table and a chair.​

2 tables and 3 chairs together cost $1900 wher93 tables and 2 chairs together cost $2600. Find the cost of a table and a chair.