Well, anything in absolute value lines become positive, so the equation would be:
3/4+5+x=13/4
Next we subtract 3/4 to both sides to start separating the variable (x).
So, 5+x=10/4
Next, we subtract 5 from both sides. (5= 20/4)
And we get: x=-10/4.
I hope this helps!
Substitute the coordinates of points to the equation.


1. Use Difference of squares: a^2-b^2=(a+b)(a-b)
(x+k)(x-k)=0
2. Solve for x and k
x=+-k
k=+-x
Answer:
(-5, 3)
Step-by-step explanation:
Elimination seems like the best method to use here.
x+y=-2
x-y=-8
---------
2x=-10
Divide everything by two
x=-5
Now plug it back into one of the original equations,
-5+y=-2
Add 5 to everything
y=3