<h2>
The stone fall in air for 7 seconds and fall in water for 5 seconds.</h2>
Step-by-step explanation:
Total distance to sea bed = 127 m
Let the distance traveled in air be s.
Distance traveled in water = 127 - s
Average velocity in air = 16 m/s
Average velocity in water = 3 m/s
Distance traveled in air = Average velocity in air x Time in air
s = 16 x t₁
Distance traveled in water = Average velocity in water x Time in water
127-s = 3 x t₂
We have total time is 12 seconds
That is
t₁ + t₂ = 12
We have
s = 16 x t₁
112 = 16 x t₁
t₁ = 7 s
t₁ + t₂ = 12
7 + t₂ = 12
t₂ = 5 s
The stone fall in air for 7 seconds and fall in water for 5 seconds.
Answer:
62
Step-by-step explanation:
(82-2)-2× 3^7 ÷ 3^3
___________
3^2
80 - 2 × 3^4
_________
3^2
80 - 2 × 3^2
80 - 2 × 9
80 - 18
62
There are no "of the following" listed, but when you multiply a length by 2/3, you're indicating that you are only "using" 2/3 of that length, which is smaller by a third. Regardless of what your original lengths of the diagonals are, the area is going to be smaller. By 2/3, to be exact.
Answer:
A. D: 0 ≤ b ≤ 10 R: 0 ≤ W(b) ≤ 120
Step-by-step explanation:
Since b represents the number of birdhouses, it is reasonable for that to have non-negative values. The maximum material availability means that b > 10 is not of practical use. This eliminates choices B and D.
Since W represents the amount of wood required for b birdhouses, it is reasonable for the range of it to match 12 times the domain: 12·0 = 0 to 12·10 = 120. This eliminates choice C.
The appropriate choice is ...
A. D: 0 ≤ b ≤ 10 R: 0 ≤ W(b) ≤ 120
