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katrin2010 [14]
3 years ago
8

A square current-carrying loop is placed in a uniform magnetic field B with the plane of the loop parallel to the magnetic field

. (See drawing). The dashed line is the axis of rotation. The magnetic field exerts:
a) a net torque, but not a net force, on the loop

b) a net force and a net torque on the loop

c) a net force, but not a net torque, on the loop

d) neither a net force nor a net torque on the loop
Physics
1 answer:
Radda [10]3 years ago
5 0

Answer:

(A) a net torque but no net force on the loop.

Explanation:

The total force on the loop is zero because the forces on the opposite sides of the loop are equal but act in opposite directions and as a result they cancel each other out. The two forces on opposite sides to the axis of rotation each give rise to a torque about the axis of rotation. This torque is directed along the axis of rotation.

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What are common features of both the MMPI-2 and CPI? Select all that apply.
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We drive at a speed of 20 km/h for 3 hours. Then we drive 4 hours at 30 km/h. Calculate our average speed.
Afina-wow [57]

First speed = 20km/h

Time = 3 hours

Distance = 3×20

<h3> = <u>60 km</u></h3>

Second speed = 30km/h

Time = 4 hours

Distance = 4×30

<h3> = <u>120 km</u></h3>

Total distance = 60+120 = <u>180km</u>

Total time = 3+4 =<u> 7 hours</u>

Average speed = 180/7

<h3> = <u>25.71</u><u> </u><u>km</u><u>/</u><u>h</u></h3>

Hope this will help...

4 0
2 years ago
Read 2 more answers
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