The net force is 12 N to the left.
        
                    
             
        
        
        
Answer:
s = 20 m
Explanation:
given,
mass of the roller blader = 60 Kg
length = 10 m
inclines at = 30°
coefficient of friction = 0.25
using conservation of energy
 
 
 
u = 9.89 m/s
Using second law of motion  
ma =μ mg
a = μ g
a = 0.25 x 9.8
a = 2.45 m/s²
Using third equation of motion ,  
v² - u² = 2 a s
0² - 9.89² = 2 x 2.45 x s
s = 20 m
the distance moved before stopping is 20 m
 
        
             
        
        
        
Answer:
Energy required = 3169.34 Joules.
Explanation:
The quantity of energy (Q) required can be determined by;
Q = mcΔθ
Where: m is the mass, c is the specific heat and Δθ is the change in temperature.
But, m = 96.7 kg, c = 0.874 J/(kg
), 
 = 
 and 
 = 
.
So that,
Q = mc(
 - 
)
    = 96.7 x 0.874 x (
 - 
)
   = 96.7 x 0.874 x 37.5
   = 3169.3425
Q = 3169.34
    = 3.2 KJ
The amount of energy required is 3169.34 Joules.