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Inga [223]
1 year ago
9

if you're shopping for a rack switch, what component on the switch tells you it can be mounted to a rack?

Physics
1 answer:
Tatiana [17]1 year ago
6 0

if you're shopping for a rack switch, the component on the switch that tells you it can be mounted to a rack is the:

  • Rack ears

<h3>What are rack ears?</h3>

Rack ears are L-shaped objects that can be used to hold a rack switch firmly to the support walls. Rack ears are often found at the front panel of the rack which is to be mounted.

When a person purchases a rack switch and finds the rack ears there, it is a signal that the item can be secured firmly to rails. Sometimes, the rack ears also appear as extensions.

Learn more about rack ears here:

brainly.com/question/13318148

#SPJ4

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Answer:

The answer is A

Explanation:

The octopus’s tentacle keeps moving right after it is bitten off

5 0
2 years ago
Which requires more work, carrying a 420 N knapsack up a 200 m hill or carrying a 210 knapsack up a 400 m hill? Why?
Katen [24]

Answer:

b

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3 years ago
A wheel of radius R, mass M, and moment of inertia I is mounted on a frictionless, horizontal axles. A light cord wrapped around
Alex_Xolod [135]

Answer:

\alpha =\frac{m*g*R}{I-m*R^2}

a = \frac{m*g*R^2}{I-m*R^2}

T=\frac{I*m*g}{I-m*R^2}

Explanation:

By analyzing the torque on the wheel we get:

T*R=I*\alpha    Solving for T:   T=I/R*\alpha

On the object:

T-m*g = -m*a    Replacing our previous value for T:

I/R*\alpha-m*g = -m*a

The relation between angular and linear acceleration is:

a=\alpha*R

So,

I/R*\alpha-m*g = -m*\alpha*R

Solving for α:

\alpha =\frac{R*m*g}{I+m*R^2}

The linear acceleration will be:

a =\frac{R^2*m*g}{I+m*R^2}

And finally, the tension will be:

T =\frac{I*m*g}{I+m*R^2}

These are the values of all the variables: α, a, T

8 0
3 years ago
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zhuklara [117]

Answer:In a series circuit, adding more resistors increases total resistance and thus lowers current. But the opposite is true in a parallel circuit because adding more resistors in parallel creates more choices and lowers total resistance. If the same battery is connected to the resistors, current will increase.

Explanation:

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