Answer:
1 m
Explanation:
L = 100 m
A = 1 mm^2 = 1 x 10^-6 m^2
Y = 1 x 10^11 N/m^2
F = 1000 N
Let the cable stretch be ΔL.
By the formula of Young's modulus
ΔL = 1 m
Thus, the cable stretches by 1 m.
The larger the push, the larger the change in velocity. This is an example of Newton's Second Law of Motion which states that th
2 answers:
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Answer:
Power will be 0.2023 watt
And when amplitude is halved then power will be 0.0505 watt
Explanation:
We have given mass of the Piano wire m = 2.60 gram = 0.0026 kg
Length of wire l = 84 cm = 0.84 m
So mass density
Tension in the wire T = 25 N
Frequency f = 120 Hz
So angular frequency
And amplitude A = 1.6 mm = 0.0016 m
We have to find the generated power
Power is given by
From the relation we can see that power
So if amplitude is halved then power will be times
So power will be equal to