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tatuchka [14]
3 years ago
8

The larger the push, the larger the change in velocity. This is an example of Newton's Second Law of Motion which states that th

e acceleration an object experiences is _____ .
Physics
2 answers:
Paul [167]3 years ago
6 0
According to Newton, an object will only accelerate if there is a net or unbalanced forceacting upon it. The presence of an unbalanced force will accelerate an object - changing its speed, its direction, or both its speed and direction.
Aneli [31]3 years ago
4 0

Newton's Second Law of Motion which states that the acceleration an object experiences is directly proportional to the force applied to it

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If the distance between two asteroids is doubled, the gravitational force they exert on each other will.
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The force will be 4 times smaller.
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A charge is moving in a magnetic field that points to the left. What direction can the charge move and experience no magnetic fo
tiny-mole [99]
The answer is left and right. 
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What force is required to cause a 5 kg bowling ball to accelerate at 4 m/s2​
Scorpion4ik [409]

Answer:

20 N

Explanation:

By Newton's 2nd law,

The rate of change of momentum is directly proportional to the unbalance force applied on the object,

By that you can get the equation,

F = ma

  = 5 × 4 = 20 N

4 0
3 years ago
I have a density of 1.61g/cm^3 and a mass of 28g. Find the missing value
Tamiku [17]

The missing value is the 'k' that should appear between '28' and 'g' .

Nobody has a mass of 28g.

My new grandson, who was born yesterday (January 29, 2019), had a mass of 4,039g at birth.  

Mother and son are happy and resting comfortably today, in Kfar Tapuach, Samaria, Israel.

8 0
3 years ago
A spotlight on the ground shines on a wall 12 meters away. If a man 2 meters high walks away from the spotlight towards the wall
nordsb [41]

Answer: The length of the shadow on the wall is decreasing by 0.6m/s

Explanation:

the specified moment in the problem, the man is standing at point D with his head at point E.

At that moment, his shadow on the wall is y=BC.

The two right triangles ΔABC and ΔADE are similar triangles. As such, their corresponding sides have equal ratios:

ADAB=DEBC

8/12=2/y,∴y=3 meters

If we consider the distance of the man from the building as x then the distance from the spotlight to the man is 12−x.

(12−x) /12=2/y

1− (1 /12x )=2 × 1/y

Let's take derivatives of both sides:

−1 / 12dx = −2 × 1 / y^2 dy

Let's divide both sides by dt:

−1/12⋅dx/dt=−2/y^2⋅dy/dt

At the specified moment:

dxdt=1.6 m/s

y=3

Let's plug them in:

−1/121.6) = - 2/9 × dy/dt

dy/dt = 1.6/12 ÷ 2/9

dy/dt = 1.6/12 × 9/2

dy/dt = 14.4/24 = 0.6m/s

5 0
3 years ago
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