The metallic radius (r) of au is 144.2pm
A face-centered cubic unit cell structure is made up of atoms arranged in a cube with six additional whole atoms placed in the centre of each cube face and a fraction of an atom at each of the cube's four corners. Eight additional unit cells share the atoms at the cube's corner.
Atoms in an FCC crystal are in contact along the unit cell's diagonal. 4r = √2 a, where r is the radius of an atom and a is the edge length of a unit cell.
Putting the values in the above expression,we get
r = √2×408 / 4
r =
r =
r = 144.2 pm
Therefore, The metallic radius (r) of au is 144.2pm
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The time period of the pendulum is affected by the acceleration due to gravity. The tension does not have any effect on the time period of the pendulum and also the mass of the bob does not effect the time period of the pendulum.
Hence, if the gravity increases then the time period of the pendulum will decreases and it will swing faster.
Complete Question
The complete question is shown on the first uploaded image
Answer:
Explanation:
From he question we are told that
The first mass is
The second mass is
From the question we can see that at equilibrium the moment about the point where the string holding the bar (where are hanged ) is attached is zero
Therefore we can say that
Making x the subject of the formula
Looking at the diagram we can see that the tension T on the string holding the bar where are hanged is as a result of the masses (
)
Also at equilibrium the moment about the point where the string holding the bar (where () and
are hanged ) is attached is zero
So basically
Making subject
