Answer:t=0.1205
Explanation:
Given
Refractive index of oil
Wavelength of red light =675 mm
Condition for constructive interference is
For m= 1 i.e. for minimum thickness
Metallic gold crystallizes in a face-centered cubic lattice, with one au atom per lattice point. if the edge length of the unit
1 answer:
The metallic radius (r) of au is 144.2pm
A face-centered cubic unit cell structure is made up of atoms arranged in a cube with six additional whole atoms placed in the centre of each cube face and a fraction of an atom at each of the cube's four corners. Eight additional unit cells share the atoms at the cube's corner.
Atoms in an FCC crystal are in contact along the unit cell's diagonal. 4r = √2 a, where r is the radius of an atom and a is the edge length of a unit cell.
Putting the values in the above expression,we get
r = √2×408 / 4
r =
r =
r = 144.2 pm
Therefore, The metallic radius (r) of au is 144.2pm
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The magnetic field strength is 9.47 ×10⁻⁴ T
The energy density at the center of the loop is 0.36 J/m³
<h3>Calculating Magnetic field strength & Energy density </h3>From the question, we are to find the magnetic field strength
The magnetic field strength of a loop can be calculated by using the formula,
Where B is the magnetic field strength
is the permeability of free space
is the current
and R is the radius
From the give information,
and
Putting the parameters into the formula, we get
Hence, the magnetic field strength is 9.47 ×10⁻⁴ T
Now, for the energy density
Energy density can be calculated by using the formula,
Where is the energy density
Then,
Hence, the energy density at the center of the loop is 0.36 J/m³
Learn more on Magnetic field stregth & Energy density here: brainly.com/question/13035557