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hram777 [196]
3 years ago
5

Here are scores for two softball teams for seven innings. Rosie's Riveters beat The Susan Bees by how many runs?

Mathematics
2 answers:
Rashid [163]3 years ago
8 0
13-10=3, they won by 3 runs.
dezoksy [38]3 years ago
3 0

Answer:

3

Step-by-step explanation:

Rosie's Riveters

1 + 3 + 4 + 2 + 1 + 0 + 2 = 13

Susan Bees

0 + 0 + 5 + 3 + 0 + 1 + 1 = 10

To find out how many they beat the Susan Bees by you need to subtract.

13 - 10 = 3

Rosie's Riveters beat the Susan Bees by 3 runs.

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If the angles of a quadrilateral are 140, 80, 60, 80 then what type of quadrilateral could it be?
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Im sorry but, a friend told it was a rectangle, im sure if thats  a good enough answer but if it isn't im sorry

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3 years ago
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In 2008 the Better Business Bureau settled 75% of complaints they received (USA Today, March 2, 2009). Suppose you have been hir
Ede4ka [16]

Answer:

Explained below.

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

 \mu_{\hat p}= p

The standard deviation of this sampling distribution of sample proportion is:

 \sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

(a)

The sample selected is of size <em>n</em> = 450 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{450}}=0.0204

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0204^{2}).

(b)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.96

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.95.

(c)

The sample selected is of size <em>n</em> = 200 > 30.

Then according to the central limit theorem the sampling distribution of sample proportion is normally distributed.

The mean and standard deviation are:

\mu_{\hat p}=p=0.75\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.75(1-0.75)}{200}}=0.0306

So, the sampling distribution of sample proportion is \hat p\sim N(0.75,0.0306^{2}).

(d)

Compute the probability that the sample proportion will be within 0.04 of the population proportion as follows:

P(p-0.04

                                          =P(-1.31

Thus, the probability that the sample proportion will be within 0.04 of the population proportion is 0.81.

(e)

The probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 450 is 0.95.

And the probability that the sample proportion will be within 0.04 of the population proportion if the sample size is 200 is 0.81.

So, there is a gain in precision on increasing the sample size.

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3 years ago
Mrs. Royal has 99 Royal Recognition awards to give out. Each class received 9 awards. How many classes received awards
Art [367]

Answer:

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Step-by-step explanation:

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Answer:

44

Step-by-step explanation:

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Answer:

No

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