Write a function rule for the table.

Find two integers whose sum is -20 and product is 99

Brums [2.3K]

Answer:

Step-by-step explanation:

let the integers be x and y

x+y=-20

y=-20-x

xy=99

x(-20-x)=99

-20x-x²=99

x²+20x+99=0

x²+11x+9x+99=0

x(x+11)+9(x+11)=0

(x+11)(x+9)=0

x=-11,-9

when x=-11

-11+y=-20

y=-20=11=-9

when x=-9

-9+y=-20

y=-20+9=-11

so integers are -11,-9

8 0

2 years ago

Read 2 more answers

A customer purchased a total of 16 washcloths and towels. Each washcloth cost $10.50 and each towel cost $15.00. The customer sp

IgorC [24]

Answer:

3

Step-by-step explanation:

10.50 x 3 = 31.5

15 x 13 = 195

195 + 31.5 = 226.50

8 0

2 years ago

What is 52/6 in simplest form

zimovet [89]

52/6 in simplest form is 8 2/3 I got the answer 8 2/3 because 6 can go into 52 8 times and there is a remainder the remainder that I got was 4 . I'll put the remainder over the denominator which is 6. So right now I would have 8 4/6 but this fraction can be simplied again by 2 so the final answer is 8 2/3

3 0

3 years ago

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What is the height of a triangular prism that has a height of 9 meters and a base with the following deminsions 4m 14m

Andrew [12]

Answer:

252m^3

Step-by-step explanation:

A solid having a triangular base is what we call a triangular prism. For every prism, its volume is always equal to the area of its base times its height. In other words:

V = AxH

V - volume

A- area

H - height of prism

We know that:

h = 4 m (side of base)

b = 14 (other base side)

A = bh/2 = 14x4/2 = 28 m^2

And then: V = A x H = 28 x 9 = 252 m^3

6 0

3 years ago

To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil

Fiesta28 [93]

Answer:

The sample has not met the required specification.

Step-by-step explanation:

As the average of the sample suggests that the true average penetration of the sample could be greater than the 50 mils established, we formulate our hypothesis as follow

$H_0$ : The true average penetration is 50 mils

$H_a$ : The true average penetration is > 50 mils

Since we are trying to see if the true average is greater than 50, this is a right-tailed test.

If the level of confidence is α = 0.05 then the $z_\alpha$ score against we are comparing with, is 1.64 (this is because the area under the normal curve N(0;1) to the right of 1.64 is 0.05)