Write a function rule for the table.

36 creates of apples. each creat has 25 kgs of apples. they sell 486,235 games of apples. how many grams are left?

valentinak56 [21]

The grams of apples left is 413765 grams

<h3>How to determine the value</h3>

From the information given, we have that:

There are 36 crates of apples
Each contains 25 kilograms of apples
486,235 grams of apples were sold

If we have 36 crates, let's determine the the total grams of apples

1 crate = 25 kilograms = 25000 grams

36 crates = x

x = 25000 × 36

x = 900000 grams

The total grams of apple is 900000 grams

The grams left = Total - sold = 900000 - 486,235 = 413765 grams

Thus, the grams of apples left is 413765 grams

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8 0

2 years ago

The amount of money spent on textbooks per year for students is approximately normal.

Ostrovityanka [42]

Answer:a

a

$336.04 < \mu < 443.96$

b

The margin of error will increase

c

The margin of error will decreases

d

The 99% confidence interval is $0.4107 < p < 0.4293$

Step-by-step explanation:

From the question we are told that

The sample size $n = 19$

The sample mean is $\= x = \$\ 390$

The standard deviation is $\sigma = \$ \ 120$

Given that the confidence level is 95% then the level of significance is mathematically represented as

$\alpha = 100 - 95$

$\alpha = 5 \%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the normal distribution table

So

$Z_{\frac{\alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma}{\sqrt{n} }$

=> $E = 1.96 * \frac{120}{\sqrt{19} }$

=> $E = 53.96$

The 95% confidence interval is

$\= x - E < \mu < \= x + E$

=> $390 - 53.96 < \mu < 390 - 53.96$

=> $336.04 < \mu < 443.96$

When the confidence level increases the $Z_{\frac{\alpha }{2} }$ also increases which increases the margin of error hence the confidence level becomes wider

Generally the sample size mathematically varies with margin of error as follows

$n \ \ \alpha \ \ \frac{1}{E^2 }$

So if the sample size increases the margin of error decrease

The sample proportion is mathematically represented as

$\r p = \frac{210}{500}$

$\r p = 0.42$

Given that the confidence level is 0.99 the level of significance is $\alpha = 0.01$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 2.58$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} }* \sqrt{ \frac{\r p (1- \r p )}{n} }$

=> $E = 0.42 * \sqrt{ \frac{0.42 (1- 0.42 )}{ 500} }$

=> $E = 0.0093$

The 99% confidence interval is

$\r p - E < p < \r p + E$

$0.42 - 0.0093 < p < 0.42 + 0.0093$

$0.4107 < p < 0.4293$

4 0

3 years ago

H(x)=x-4 what’s is the domain of h?

Kazeer [188]

Answer:

all real number

Step-by-step explanation:

since h(x) is polynomial function

5 0

2 years ago

20 POINTS AND BRAINLIEST!! Write an exponential function in the form y=ab^x

Rudik [331]

Answer:

$y=13(4)^x$

Step-by-step explanation:

We have the exponential function of the form:

$y=ab^x$

And it goes through the points (0, 13) and (3, 832).

Hence, when we substitute in 0 for x, we should get 13 for y. Therefore:

$13=ab^0$

Since anything to the zeroth power is 1, this yields:

$a=13$

So, we determined that the value of a is 13.

So, our function is now:

$y=13b^x$

We will need to determine b. We know that y equals 832 when x is 3. Hence:

$832=13(b)^3$

Divide both sides by 13:

$b^3=64$

Take the cube root of both sides:

$b=4$

Hence, our b value is 4.

Therefore, our entire equation is:

$y=13(4)^x$

3 0

3 years ago

A recent gasoline survey said that the national average price of gasoline was $1.298 a gallon. It was felt that gasoline price i

slava [35]

Answer:

alternative hypothesis : H₁ :

Recent Gasoline surveys felt that gasoline price in Texas was significantly lower than the national average

Alternative Hypothesis : H₁: μ < $1.298 a gallon

Step-by-step explanation:

Explanation:-

Given A recent gasoline survey said that the national average price of gasoline was $1.298 a gallon

Population average μ= $1.298 a gallon

sample size 'n' = 37

Sample mean (x⁻) = $1.192 a gallon

Sample standard deviation 'S' = $0.0436

Null hypothesis :H₀ : μ = $1.298 a gallon

Alternative Hypothesis : μ < $1.298 a gallon

Degrees of freedom : ν = n-1= 37-1=36

t₀.₀₂₅ = 1.688

Test statistic

$t = \frac{x^{-}-mean }{\frac{S}{\sqrt{n} } }$

$t = \frac{1.192-1.298 }{\frac{0.0436}{\sqrt{37} } }$

t = -14.8044

|t| = |-14.8044| > 1.688

Null hypothesis is rejected

Alternative hypothesis is accepted

Recent Gasoline surveys felt that gasoline price in Texas was significantly lower than the national average

6 0

2 years ago