The answer is 2k^2 - 7k - 4 because 2k x k is 2k^2 and 2k x (-4) is -8k and 1 x k is k and 1 x (-4) is -4. So then you would get 2k^2 - 8k + k - 4 which simplifies to 2k^2 - 7k - 4 which is your answer.
Answer:
THE VALUE OF X = 3 .
Step-by-step explanation:
From the Δ RQP and Δ TSP ;
⇒ ∠ TPS = ∠ RPQ ( since both are common angle )
⇒ RQ ≈ TS ( parallel lines )
⇒ ∠ PRQ = ∠ PST ( Corresponding angle )
∴ Δ RQP ≅ Δ TSP ( BY ASA RULE )
Now ,
⇒ X = 3
The points have to have the coordinate y=4 to be on the y=4 line
only the (1, 4) point matches this, so yes it is a solution, all others not and are therefore no
The question states that both parts of Noshi's desk were shaped like trapezoids and both had a height of 3.
We know that the formula for area of a trapezoid is (a+b)/2 * h, where a and b are bases of the trapezoid and h is the height. Note: This is like any other form of trying to find the area, because we are doing base times height, however, we need to divide the sum of the bases by 2 to find the average base length.
Let's call the first trapezoid on the left Trapezoid A and the second slanted trapezoid Trapezoid B.
Area of Trapezoid A = (a+b)/2 * h = (5+8)/2 * 3 = 13/2 * 3 = 6.5 * 3 = 19.5 feet
Area of Trapezoid B = (a+b)/2 * h = (4+9)/2 * 3 = 13/2 * 3 = 6.5 * 3 = 19.5 feet
To find the area of Noshi's total desk, we simply need to add the areas of Trapezoid A and Trapezoid B together.
19.5 feet + 19.5 feet = 39 feet
Therefore, the area of Noshi's desk is 39 feet.
Hope this helps! :)
Answer:
x is less than or equal to 64/-3
