Answer:
1/8
Step-by-step explanation:
sin²(π/8) − cos⁴(3π/8)
Use power reduction formulas:
1/2 (1 − cos(2×π/8)) − 1/8 (3 + 4 cos(2×3π/8) + cos(4×3π/8))
Simplify:
1/2 (1 − cos(π/4)) − 1/8 (3 + 4 cos(3π/4) + cos(3π/2))
1/2 (1 − √2/2) − 1/8 (3 + 4 (-√2/2) + 0)
1/2 − √2/4 − 1/8 (3 − 2√2)
1/2 − √2/4 − 3/8 +√2/4
1/2 − 3/8
1/8
Answer:
A = 3, B = 5.2
Step-by-step explanation:
i think that is right, i hope this helps.
Answer:
t2 = 52.8 hours
it will take 52.8 hours if its flow is reduced to 5 litres per minute.
Step-by-step explanation:
The volume of the swimming pool can be written as;
Volume V = flow rate × time
V = R×t
V = R1×t1 = R2×t2
R1×t1 = R2×t2
t2 = R1×t1/R2 ........1
Given;
Flow rate R1 = 12 litres per minute
Flow rate R2 = 5 litres per minute
time t1 = 22 hours
Substituting the given values into equation 1;
t2 = R1×t1/R2 = 12×22/5
t2 = 52.8 hours
it will take 52.8 hours if its flow is reduced to 5 litres per minute.
It would be: P * R * T /100
= 43800 * 4.8 * 2 /100
= 420480 / 100
= 4204.80
So, your final answer is $4204.80
Hope this helps!
