Answer:
B
Step-by-step explanation:
y=n(x+5)(x-3)
or y=n(x²-3x+5x-15)
or y=n(x²+2x-15)
=n(x²+2x+1-1-15)
=n(x+1)²-16n
y -coordinate of vertex=-16n
<u>Answer-</u>
<em>The amount will be </em><em>$8944.62</em><em> after 5 years.</em>
<u>Solution-</u>
We know that,
![\text{FV of annuity}=P[\dfrac{(1+r)^n-1}{r}]](https://tex.z-dn.net/?f=%5Ctext%7BFV%20of%20annuity%7D%3DP%5B%5Cdfrac%7B%281%2Br%29%5En-1%7D%7Br%7D%5D)
Where,
P = Payment = $50 monthly
r = rate of interest compounded monthly= 
n = number of period = 5 years = 5×12 = 60 months
Putting the values in the formula,
![\text{FV of annuity}=50[\dfrac{(1+0.0325)^{60}-1}{0.0325}]](https://tex.z-dn.net/?f=%5Ctext%7BFV%20of%20annuity%7D%3D50%5B%5Cdfrac%7B%281%2B0.0325%29%5E%7B60%7D-1%7D%7B0.0325%7D%5D)
![=50[\dfrac{(1.0325)^{60}-1}{0.0325}]](https://tex.z-dn.net/?f=%3D50%5B%5Cdfrac%7B%281.0325%29%5E%7B60%7D-1%7D%7B0.0325%7D%5D)
![=50[\dfrac{6.8140-1}{0.0325}]](https://tex.z-dn.net/?f=%3D50%5B%5Cdfrac%7B6.8140-1%7D%7B0.0325%7D%5D)
![=50[\dfrac{5.8140}{0.0325}]](https://tex.z-dn.net/?f=%3D50%5B%5Cdfrac%7B5.8140%7D%7B0.0325%7D%5D)
Therefore, the amount will be $8944.62 after 5 years.
Answer:
- (6-u)/(2+u)
- 8/(u+2) -1
- -u/(u+2) +6/(u+2)
Step-by-step explanation:
There are a few ways you can write the equivalent of this.
1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...
(-u+6)/(u+2)
Or, you can rearrange the terms so the leading coefficient is positive:
(6 -u)/(u +2)
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2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.
-(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)
or
8/(u+2) -1
Of course, anywhere along the chain of equal signs the expressions are equivalent.
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3) You can separate the numerator terms, expressing each over the denominator:
(-u +6)/(u+2) = -u/(u+2) +6/(u+2)
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4) You can also multiply numerator and denominator by some constant, say 3:
-(3u -18)/(3u +6)
You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:
(1+x^2)(6 -u)/((1+x^2)(u+2))
1) Combining like terms, we get x^2 + 5x, which is a binomial.
2) Combining like terms, we get x^3 + 3x^2, which is a binomial.
3) Combining like terms, we get 4x^3 + x^2 - x, which is a trinomial.
4) I can't answer this because there's an asterisk in place of the exponent.
Answer:
I'm getting points
Step-by-step explanation:
so I can ask questionss
