Let x be the first computer. Let y be the first computer. We know that Work = 1 / Time.
If the work together, work can be done in 30 seconds. Thus, we have:
1/x + 1/y = 1/30
If x will finish in 50 seconds, we need to compute how many seconds y can finish the same work. Thus solving for y, we have the equation below:
1/50 + 1/y = 1/30
1/y = 1/30 - 1/50
1/y = 1/75
The second computer can finish the same work in 75 seconds.
104.16666 repetant times larger
Answer: the answer to the question is a7x
Step-by-step explanation:
