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Citrus2011 [14]

3 years ago

6

Alex scored 13 points in the basketball game this was 1/5 of the total points the team scored write and solve an equation to det

ermine the total points t the team scored PLEASE show work thanks;)

1 answer:

ziro4ka [17]3 years ago

4 0

1/5x=13 (5)1/5x=13(5) X=65

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The following data are the distances between a sample of 20 retail stores and a large distribution center. The distances are in

sesenic [268]

Answer:

Variance = 1,227.27

Standard deviation = 35.03

Step-by-step explanation:

To calculate these, we use the following formulas:

Mean = (sum of the values) / n

Variance = ((Σ(x - mean)^2) / (n - 1)

Standard deviation = Variance^0.5

Where;

n = number of values = 20

x = each value

Therefore, we have:

Sum of the values = 29 + 32 + 36 + 40 + 58 + 67 + 68 + 69 + 76 + 86 + 87 + 95 + 96 + 96 + 99 + 106 + 112 + 127 + 145 + 150 = 1,674

Mean = 1,674 / 20 = 83.70

Variance = ((29-83.70)^2 + (32-83.70)^2 + (36-83.70)^2 + (40-83.70)^2 + (58-83.70)^2 + (67-83.70)^2 + (68-83.70)^2 + (69-83.70)^2 + (76-83.70)^2 + (86-83.70)^2 + (87-83.70)^2 + (95-83.70)^2 + (96-83.70)^2 + (96-83.70)^2 + (99-83.70)^2 + (106-83.70)^2 + (112-83.70)^2 + (127-83.70)^2 + (145-83.70)^2 + (150-83.70)^2) / (20 - 1) = 23,318.20 / 19 = 1,227.27

Standard deviation = 1,227.27^0.5 = 35.03

5 0

2 years ago

Help again lol don’t feel like thinking

Alexxandr [17]

Answer:

point O, it is located on (-4.5, -7)

6 0

2 years ago

In Triangle WVU, what sides include Angle V?

NeTakaya

Answer:

∴ $WV$ and $UV$ this two sides include $\angle V$

Step-by-step explanation:

Given;

A triangle $WVU$

We can see the figure of the triangle $WVU$

Where the $\angle V$ or $\angle WVU$ made by two sides $WV$ and $UV$ .

So $WV$ and $UV$ this two sides include $\angle V$

7 0

2 years ago

Justin was looking for a birthday card for his sister. There were 9 funny cards, 7 serious cards, and 5 musical cards. How many

madam [21]

Just add. 7 + 9 + 5 = 21 So the answer is A.21

5 0

2 years ago

Read 2 more answers

One of Julian's friends also has a rectangular aquarium. The dimensions of his friend's tank are each exactly 1 1/4 times the di

daser333 [38]

Answer:

468.75 square inches

Step-by-step explanation:

Let the length of Julian's tank be x

Let the width of Julian's tank be y

So, Area of Julian's tank= $Length \times Width =xy$

Since we are given that Julian's tank is approximately 300 square inches

So, $xy=300$ --1

Now we are given that The dimensions of his friend's tank are each exactly $1\frac{1}{4} =\frac{5}{4}$ times the dimensions of Julian's tank.

So,length of his friend's tank = $\frac{5}{4}x$

So,width of his friend's tank = $\frac{5}{4}y$

So, Area of his friend's tank= $\frac{5}{4}x \times \frac{5}{4}y$

= $\frac{25}{16}xy$

= $\frac{25}{16}(300)$ (Using 1)

= $468.75$

Hence the approximate area of the rectangular base of his friend's tank is 468.75 square inches.

So, Option D is correct.

8 0

3 years ago