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Papessa [141]
4 years ago
10

05. When a gold pebble is placed in a graduated cylinder that contains 12.0 mL of water, the water level rises

Chemistry
1 answer:
OLga [1]4 years ago
6 0

Answer:

142.82 g

Explanation:

The following data were obtained from the question:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Density of gol= 19.3 g/cm³

Mass of gold =.?

Next, we shall determine the volume of the gold. This can be obtained as follow:

Volume of water = 12 mL

Volume of water + gold = 19.4 mL

Volume of gold =.?

Volume of gold = (Volume of water + gold) – (Volume of water)

Volume of gold = 19.4 – 12

Volume of gold = 7.4 mL

Finally, we shall determine the mass of the gold as follow:

Note: 1 mL is equivalent to 1 cm³

Volume of gold = 7.4 mL

Density of gol= 19.3 g/cm³ = 19.3 g/mL

Mass of gold =?

Density = mass /volume

19.3 = mass of gold /7.4

Cross multiply

Mass of gold = 19.3 × 7.4

Mass of gold = 142.82 g

Therefore, the mass of the gold pebble is 142.82 g

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3 years ago
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Over [174]

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Both sodium and calcium.

Explanation:

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5 0
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Answer:

9842kJ of energy are released

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Based on the reaction:

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<em>When 2 moles of C₄H₁₀ react with 13 moles of O₂ there are released 5720 kJ of energy</em>

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<em> </em>

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3.441 moles C₄H₁₀ ₓ (5720kJ / 2 moles C₄H₁₀) = <em>9842kJ of energy are released</em>

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