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Verizon [17]
3 years ago
7

I NEED HELP PLEEEEAASSEEEEE

Chemistry
1 answer:
In-s [12.5K]3 years ago
4 0

Answer:

Student 3!

Hope This Helps!

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How do you find the number of moles of copper in copper gluconate? In my experiment I used 1.4 g of copper gluconate, and ended
Kipish [7]

<u>Answer:</u> 0.0016 moles of copper are present in copper gluconate

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

Given mass of copper = 0.1 g

Molar mass of copper = 63.55 g/mol

Plugging values in equation 1:

\text{Moles of copper}=\frac{0.1g}{63.55g/mol}=0.0016 mol

Hence, 0.0016 moles of copper are present in copper gluconate

7 0
3 years ago
What is the conservation of mass pertains the chemical change and physical change?
Leokris [45]

Answer:

Hey mate......

Explanation:

This is ur answer......

<h3>The Law of Conservation of Mass</h3>

<em>Matter can change form through physical and chemical changes, but through any of these changes, matter is conserved. The same amount of matter exists before and after the change—none is created or destroyed. This concept is called the Law of Conservation of Mass.</em>

<em>The Law of Conservation of Matter also states that the matter cannot be created or destroyed. In a physical change, substances can change form, but the total mass remains the same. In a chemical change, the total mass of the reactants always equals the total mass of the products.</em>

Hope it helps!

Brainliest pls!

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6 0
3 years ago
Read 2 more answers
If a naturally occurring sample of an unidentified element is found to contain three isotopes (A, B, and C) and consists of 90.5
aivan3 [116]

If a naturally occurring sample of an unidentified element is found to contain three isotopes (A, B, and C) and consists of 90.5% isotope A (mass number 20), 0.3% isotope B (mass number 21), and 9.3% isotope C (mass number 22), the atomic weight of the element measured from the sample will be greater than 21 amu.

To calculate the average atomic mass, multiply the fraction through the mass number for every isotope, then add them together. Whenever we do mass calculations concerning elements or compounds (combos of elements), we usually use average atomic loads.

For instance, carbon-14 is a radioactive isotope of carbon that has six protons and 8 neutrons in its nucleus. We name it carbon-14 because the overall range of protons and neutrons within the nucleus also called the mass number, provides up to fourteen (6+8=14).

Together, the quantity of protons and the range of neutrons determine an detail's mass variety. Due to the fact, that an element's isotopes have barely unique mass numbers, the atomic mass is calculated by obtaining the suggested mass numbers for its isotopes.

Learn more about atomic mass here brainly.com/question/1358482

#SPJ4

3 0
2 years ago
Formic acid, hcooh, is a weak electrolyte. what solutes are present in an aqueous solution of this compound? write the chemical
ioda
<span>All acids form their conjugate base and a proton or H+ in an aqueous solution, in water. Since formic acid is an acid, although a weak electrolyte, it will react with water to form the conjugate base HCOO with a negative 1 charge. The other solute will be the proton H+, also written as hydronium H3O+.</span>
5 0
4 years ago
To what volume should you dilute 122 mL of an 8.20 M CuCl2 solution so that 51.0 mL of the diluted solution contains 4.40 g CuCl
BartSMP [9]

Answer:

<h2>The first thing to do here is to use the molarity and the volume of the initial solution to figure out how many grams of copper(II) chloride it contains.</h2><h2 /><h2>133</h2><h2>mL solution</h2><h2>⋅</h2><h2>1</h2><h2>L</h2><h2>10</h2><h2>3</h2><h2>mL</h2><h2>⋅</h2><h2>7.90 moles CuCl</h2><h2>2</h2><h2>1</h2><h2>L solution</h2><h2>=</h2><h2>1.051 moles CuCl</h2><h2>2</h2><h2 /><h2>To convert this to grams, use the compound's molar mass</h2><h2 /><h2>1.051</h2><h2>moles CuCl</h2><h2>2</h2><h2>⋅</h2><h2>134.45 g</h2><h2>1</h2><h2>mole CuCl</h2><h2>2</h2><h2>=</h2><h2>141.31 g CuCl</h2><h2>2</h2><h2 /><h2>Now, you know that the diluted solution must contain </h2><h2>4.49 g</h2><h2> of copper(II) chloride. As you know, when you dilute a solution, you increase the amount of solvent while keeping the amount of solute constant.</h2><h2 /><h2>This means that you must figure out what volume of the initial solution will contain </h2><h2>4.49 g</h2><h2> of copper(II) chloride, the solute.</h2><h2 /><h2>4.49</h2><h2>g</h2><h2>⋅</h2><h2>133 mL solution</h2><h2>141.32</h2><h2>g</h2><h2>=</h2><h2>4.23 mL solution</h2><h2>−−−−−−−−−−−−−− </h2><h2 /><h2>The answer is rounded to three sig figs.</h2><h2 /><h2>You can thus say that when you dilute </h2><h2>4.23 mL</h2><h2> of </h2><h2>7.90 M</h2><h2> copper(II) chloride solution to a total volume of </h2><h2>51.5 mL</h2><h2> , you will have a solution that contains </h2><h2>4.49 g</h2><h2> of copper(II) chloride.</h2>
3 0
3 years ago
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