I would love to help but I cant see the picture
Answer:
For this experiment we are going to take plate 1 as the control plate, so, in it there will be just E. coli in LB/agar; in plate 2, we are going to put E. coli in LB/agar and some ampicillin. Then, we have to wait for the E. coli colonies to form. After a while, the E. coli growth can be compared on both plates and determine if ampicillin affects or not the E. coli colonies.
Explanation:
If the ampicillin affects negatively E. coli colonies, we are going to observe that in plate 1 (control plate) there are E. coli colonies growing, but in plate 2, there is no E. coli colonies or, at least, there is a fewer number of colonies on it. If ampicillin doesn't affect E.coli, plate 1 (control) and plate 2 (ampicillin experiment) are going to be similar in number of colonies.
Calcium Carbonate is CaCO3
Hydrochloric Acid is HCl
CaCO3 + 2HCl ----> CaCl2 + H2O + CO2
Answer:
we find the chemical equilibrium constant by balancing the number of reactant and products
Explanation:
and after balancing using formula (KC) = Ratio of product / reactants
