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3 years ago

(8+9) - (8+7) x (7 x 87)

Mathematics

2 answers:

rosijanka [135]3 years ago

7 0

i think its -9118 sorry if im wrong

Stells [14]3 years ago

4 0

Answer:

-1,918

Step-by-step explanation:

PEMDAS says to do the parenthesis first. So,

8+9=17

8+7=15

7x87=609

which gives us,

17-15 x 609

Next is multiplication

15 x 609= 9,135

which gives us,

17-1,935= -1918

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What percent of 32 is 48? A.67 B.46 C.33 D.none of above

elena55 [62]

Just by giving the numbers an analisys, we are able to find the answer, specially because we have options to choose from.

32 is a big part of 48. It's more than half, which would be 24 and would correspond to 50%. Therefore, nor 46 nor 33 can be answers, because 32 is more than the half of 48, so the answer is A.

Hope it helped,

BioTeacher101

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3 years ago

Read 2 more answers

Write (p^2)^3 without exponents

Vilka [71]

Answer:

p^6

Step-by-step explanation:

We are using rule power to a power. x^2^3 = x^(2*3)

p^6

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3 years ago

A certain country has $10 billion in paper currency in circulation, and each day $50 million comes into the country's banks. The

mash [69]

Answer:

$\bf x(t)=10(1-e^{-0.005*t})$

Step-by-step explanation:

The differential equation

$\bf \displaystyle\frac{dx}{dt}=0.005(10-x)$

can be solved by separation of variables. Write the equation as

$\bf \displaystyle\frac{dx}{10-x}=0.005dt$

Integrate on both sides

$\bf \int\displaystyle\frac{dx}{10-x}=\int0.005dt\Rightarrow -ln(10-x)=0.005t+C\Rightarrow\\\\\Rightarrow ln(10-x)^{-1}=0.005t+C\Rightarrow (10-x)^{-1}=e^{0.005t}e^C$

where C is a constant.

$\bf e^C$ is also a constant and we will keep calling it C, (there is no reason to change the letter). We have then

$\bf (10-x)^{-1}=Ce^{0.005t}\Rightarrow \displaystyle\frac{1}{10-x}=Ce^{0.005t}\Rightarrow 10-x=\displaystyle\frac{1}{Ce^{0.005t}}\Rightarrow\\\\\Rightarrow x(t)=10-(1/C)e{-0.005t}$