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Hitman42 [59]
3 years ago
7

Lisa owns a "Random Candy" vending machine, which is a machine that picks a candy out of an assortment in a random fashion. Lisa

controls the probability of picking each candy. The machine is running out of "Honey Bunny," so Lisa wants to program it so that the probability of getting a candy other than "Honey Bunny" twice in a row is greater than \dfrac{9}{4} 4 9 ​ start fraction, 9, divided by, 4, end fraction times the probability of getting "Honey Bunny" in one try. Write an inequality that models the situation. Use ppp to represent the probability of getting "Honey Bunny" in one try.
Mathematics
1 answer:
tatyana61 [14]3 years ago
3 0

Answer:

[P(X_{1})\times P (X_{2})]>[\frac{9}{4}\times P (H_{1})]

Step-by-step explanation:

Let the candy "Honey Bunny" be labelled as <em>H</em> and the other candies as <em>X</em>.

It is provided that the machine is running out of "Honey Bunny".

So, Lisa wants to program it so that the probability of getting a candy other than "Honey Bunny" twice in a row is greater than 9/4 times the probability of getting "Honey Bunny" in one try.

  • Probability of getting a candy other than "Honey Bunny" twice in a row,

        P (X₁) × P (X₂)

  • Probability of getting "Honey Bunny" in one try,

        P (H₁)

The inequality is as follows:

[P(X_{1})\times P (X_{2})]>[\frac{9}{4}\times P (H_{1})]

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Answer:

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Step-by-step explanation:

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Let’s express the number of times he hits the target with x.
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Subtract x from both sides.

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Let’s substitute y in the first equation with 15 - x.

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Combine like terms on the left side.

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Add 750 on both sides.

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Divide both sides by 70.

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