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romanna [79]
3 years ago
12

Light traveling in a medium of index of refraction n1 is incident on another medium having an index of refraction n2. Under whic

h of the following conditions can total internal reflection occur at the interface of the two media? (Select all that apply.) The angle of incidence is greater than the critical angle. The angle of incidence is less than the critical angle. The indices of refraction have the relation n2 > n1. The indices of refraction have the relation n1 > n2. The light propagates at a greater speed in medium 1 than in medium 2.
Physics
1 answer:
natta225 [31]3 years ago
3 0

Answer:

Explanation:

Total internal reflections is a phenomenon where incident light rays when travelling from a denser medium or from a medium with higher refractive index to less dense medium or a medium  with lesser refractive index  ( The indices of refraction have the relation n₁ > n₂, where n₁ is the refractive index of the first medium and n₂ is the refractive index of medium 2) leads to the light ray being reflected back into the first medium instead of undergoing refraction. Usually, this occurs when the incident light rays angle to the normal is greater than a certain critical angle which is the angle when the refracted ray angle in the second medium is 90°

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Define heat...and angle of friction?​
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Explanation:

Heat is the form of energy that is transferred between systems or objects with different temperatures.....

Angle of friction : The angle which the resultant of force of limiting friction F and normal reaction R makes with direction of normal reaction R is called angle of friction...

8 0
4 years ago
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outward from a wall just above floor level. A 1.5 kg box sliding across a frictionless floor hits the end of the spring and comp
sweet [91]

Answer:

v = 0.489 m/s

Explanation:

It is given that,

Mass of a box, m = 1.5 kg

The compression in the spring, x = 6.5 cm = 0.065 m

Let the spring constant of the spring is 85 N/m

We need to find the velocity of the box (v) when it hit the spring. It is based on the conservation of energy. The kinetic energy of spring before collision is equal to the spring energy after compression i.e.

\dfrac{1}{2}mv^2=\dfrac{1}{2}kx^2

v=\sqrt{\dfrac{kx^2}{m}} \\\\v=\sqrt{\dfrac{85\times (0.065)^2}{1.5}} \\\\v=0.489\ m/s

So, the speed of the box is 0.489 m/s.

3 0
4 years ago
What happens to an object at rest if balanced forces act upon it?
Ilya [14]

3

Explanation:

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4 0
3 years ago
Bumper cars A and B undergo a collision during which the momentum of the combined system is conserved.
dexar [7]

Answer:

1. P⃗ A,i+P⃗ B,i=P⃗ A,f+P⃗ B,f

Explanation:

Collision occurs when two bodies moving at different velocities exert force on each other through colliding. Collision can either be elastic or inelastic.

For elastic collision, both energy and momentum of the bodies is conserved i.e they separates after collision.

For inelastic collision, only momentum is conserved but not energy. The body sticks together after colliding and moves with a common velocity.

According law of conservation of momentum which states that the sum or momentum of two bodies before collision is equal to the momentum of the bodies after collision.

Given two bumper cars A and B that undergoes collision during which momentum is conserved, the type of collision that exists between the bumpers is inelastic collision

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If initial momentum of A is PiA and initial momentum of B is PiB, the sum of their momentum before collision is expressed as;

PiA + PiB ... (1)

If final momentum of A is PfA and initial momentum of B is PfB, the sum of their momentum after collision is expressed as;

PfA+PfB ... (2)

According to the law, equation 1 is equal to equation 2

The fore the formula that states the law is expressed as;

PiA + PiB = PfA+PfB

5 0
3 years ago
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Amanda [17]

Solution :

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3 0
3 years ago
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