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lions [1.4K]
3 years ago
10

A motorist, traveling east on an open highway, sets his cruise control at 90.0 km/h. How far will he travel in 0.75 hours?

Physics
2 answers:
klasskru [66]3 years ago
7 0

Answer: 67.5 km

Explanation:

Distance is the velocity and time.

90 x 0.75 = total distance

The distance is represented as 67.5 km/h.

Hope this helps!

dimaraw [331]3 years ago
3 0

Answer:

<h2>The answer is 67.5 km</h2>

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

distance = velocity × time

From the question we have

distance = 90 × 0.75

We have the final answer as

<h3>67.5 km</h3>

Hope this helps you

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I think gold

Explanation:

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50 kg of water at 75o C is cooled to 25o C. How much heat was given off?
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6th grade science I mark as brainliest.​
Viktor [21]

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divide 10 by 50.

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Read 2 more answers
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sweet-ann [11.9K]

Answer:

D

Explanation:

1.) The reaction is at dynamic equilibrium.

A: Nitrogen and hydrogen combine at the same rate that ammonia breaks down.

2.) Which statement about the reaction is necessarily correct?

A: Both calcium carbonate and sodium carbonate are being produced.

3.) Both calcium carbonate and sodium carbonate are being produced.

A: The reaction is reversible.

4.) What is the fastest motion that can be measured in any frame of reference?

A: 300,000 km/s

5.) Two people are on a train that is moving at 10 m/s north. They are walking 1 m/s south relative to the train. Relative to the ground, their motion is 9 m/s north.

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8 0
3 years ago
A child of mass M is swinging on a swing set. The ropes attaching the swing to the top bar have length L. Find the gravitational
myrzilka [38]

Answer:

(a) 0

(b) 10ML

(c) 10ML(1 - cos(\theta))

(d) 10ML(1 + sin(\phi))

Explanation:

(a) When hanging straight down. The child is at the lowest position. His potential energy with respect to this point would also be 0.

(b) Since the rope has length L m. When the rope is horizontal, he is at L (m) high with respect to the lowest swinging position. His potential energy with respect to this point should be

E_h = mgh = 10ML

where g = 10m/s2 is the gravitational acceleration.

(c) At angle \theta from the vertical. Vertically speaking, the child should be at a distance of Lcos(\theta) to the swinging point, and a vertical distance of L - Lcos(\theta) to the lowest position. His potential energy to this point would be:

E_{\theta} = mgh = 10M(L - Lcos(\theta)) = 10ML(1 - cos(\theta))

(d) at angle \phi from the horizontal. Suppose he is higher than the horizontal line. This would mean he's at a vertical distance of Lsin(\phi) from the swinging point and higher than it. Therefore his vertical distance to the lowest point is L + Lsin(\phi) = L(1 + sin(\phi))

His potential energy to his point would be:

E_{\phi} = mgh = 10ML(1 + sin(\phi))

5 0
4 years ago
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