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padilas [110]
3 years ago
12

A motorist travels at 270 km in p hours at a certain average speed. an expression for the distance that this motorist travelled

in x hours at the same average speed is what
Physics
1 answer:
wel3 years ago
5 0
Average speed = total distance / time ⇒ total distance = average speed *  time

Average speed = 270 km / p hours
distance = d
hours = x

d = 270/p * x
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A 60-kg woman stands on the very end of a uniform board, which is supported one-quarter of the way from one end and is balanced.
Tasya [4]

B 30 kg because


One quarter =1/2
Kg=60

1/2 of Kg
1/2*60
30 kg
5 0
3 years ago
Suppose a uniform electric field of 4 N/C is in the positive x direction. When a charge is placed at and fixed to the origin, th
Yuliya22 [10]

Answer:

E_total = 3 N / A

Explanation:

The electric field is a vector magnitude so when adding we must use vectors, in this case as the initial field E = 4N / c goes towards the axis axis and the field created by the fixed charge (E1) is also on the axis x we can add in scalar form.

               E_total = E + E₁

the expression for the field of a point charge is

                E₁ = k q₁ / r²

for the point x = 2m, they do not say that the total field is zero, so the charge q1 must be negative

                 E_total = E -k q₁ / r₂

we substitute

                   0 = E - k q₁ / r²

                   q₁ = \frac{E r^2}{k}

let's calculate

                   q₁ = \frac{4 \ 2^2}{9 \ 10^{-9}}

                   q₁ = 1.78 10⁻⁹ C

now we can calculate the field for position x = 4 m

                   E_total = 4 - 9 10⁹  1.78 10⁻⁹ / 4²2

                   E_total = 3 N / A

8 0
3 years ago
At room temperature, sound travels at a speed of about 344 m/s in air. You see a distant flash of lightning and hear the thunder
bearhunter [10]

Answer:

<em>The lighten travels 0.853 miles.</em>

Explanation:

Sound: Sound is a form of wave which is conveyed through an elastic medium from a vibrating body to a listener.

v = 2x/t .......................................... Equation 1

making x the subject of the equation

x = vt/2........................................ Equation 2

Where v = velocity of sound in air, x = distance traveled by the sound, t = time

Given: v = 344 m/s t = 8 s

Substituting into equation 2

x = 344(8)/2

x = 1376 m.

x = 1376×0.00062 miles = 0.853 miles

<em>Thus the lighten travels 0.853 miles.</em>

4 0
3 years ago
Read 2 more answers
An object experiences an acceleration of -6.8 m/s​2.​ As a result, it accelerates from 54 m/s to a complete stop. How much dista
inessss [21]

Answer:

The distance traveled during its acceleration, d = 214.38 m

Explanation:

Given,

The object's acceleration, a = -6.8 m/s²

The initial speed of the object, u = 54 m/s

The final speed of the object, v = 0

The acceleration of the object is given by the formula,

                                      a = (v - u) / t   m/s²

       ∴                              t = (v - u) / a

                                         = (0 - 54) / (-6.8)

                                         = 7.94 s

The average velocity of the object,

                                       V = (54 + 0)/2

                                           = 27 m/s

The displacement of the object,

                                 d = V x t   meter

                                    = 27 x 7.94

                                    = 214.38 m

Hence, the distance the object traveled during that acceleration is, a = 214.38 m

3 0
3 years ago
wo parallel-plate capacitors C1 and C2 are connected in parallel to a 12.0 V battery. Both capacitors have the same plate area o
tresset_1 [31]

Complete Question

Two parallel-plate capacitors C1 and C2 are connected in parallel to a 12.0 V battery. Both capacitors have the same plate area of 5.30 cm2 and plate separation of 2.65 mm. However, the first capacitor C1 is filled with air, while the second capacitor C2 is filled with a dielectric that has a dielectric constant of 2.10.

(a) What is the charge stored on each capacitor

 (b)  What is the total charge stored in the parallel combination?

Answer:

a

   i    Q_1 =  2.124 *10^{-11} \  C

   ii    Q_2 =  4.4604 *10^{-11} \ C

b

  Q_{eq} = 6.5844 *10^{-11} \ C

Explanation:

From the question we are told that

   The  voltage of the battery is  V  = 12.0  \ V

    The  plate area of each capacitor is  A  =  5.30 \ cm^2  =  5.30 *10^{-4} \ m^2

    The  separation between the plates is  d =  2.65 \ mm =  2.65 *10^{-3} \ m

     The permittivity of free space  has a value  \epsilon_o  =  8.85 *10^{-12} \  F/m

     The  dielectric constant of the other material is  z =  2.10

The  capacitance of the  first capacitor is mathematically represented as

       C_1  =  \frac{\epsilon  *  A }{d }

substituting values

        C_1  =  \frac{8.85 *10^{-12 } *   5.30 *10^{-4} }{2.65 *10^{-3} }

       C_1  =  1.77 *10^{-12} \  F

The  charge stored in the first capacitor is  

       Q_1 =  C_1 *  V

substituting values

        Q_1 =  1.77 *10^{-12} * 12

       Q_1 =  2.124 *10^{-11} \  C

The capacitance of the second  capacitor is mathematically represented as

       C_2  =  \frac{ z * \epsilon  *  A }{d }

substituting values

       C_1  =  \frac{  2.10 *8.85 *10^{-12 } *   5.30 *10^{-4} }{2.65 *10^{-3} }

       C_1  =  3.717 *10^{-12}  \ F

The  charge stored in the second capacitor is  

      Q_2 =  C_2 *  V

substituting values

     Q_2 = 3.717*10^{-12} *  12

     Q_2 =  4.4604 *10^{-11} \ C

Now  the total charge stored in the parallel combination is mathematically represented as

     Q_{eq} =  Q_1 + Q_2

substituting values

    Q_{eq} =  4.4604 *10^{-11} + 2.124*10^{-11}

     Q_{eq} = 6.5844 *10^{-11} \ C

7 0
4 years ago
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