The lunar lander landed on the moon
Absorb kinetic energy and soften potentially damaging blows.
At the top of the height, the velocity is zero and acceleration is negative of acceleration due to gravity ( i.e 
).
The time of the ball in air is 3.2 s, so ascending time is 
.
Therefore from kinematic equation,
Substituting the values we get,
, Here v = 0 at top.
Now from equation,
, here h is the height .
So,
.
Thus, the ball reached at its maximum height of 12.48 m.
Explanation:
While studying the velocity of a cheetah over time in a spreadsheet program is given by :
y = 2.2 x + 1.2 ...(1)
We know that,
v=v₀+at ...(2)
v₀ is velocity when t = 0, v is velocity after time t, a is acceleration and t is time.
If we consider time t on x-axis and v on y axis, then only we can draw a plot of equation (2). On comparing equation (1) and (2) we get :
a = 2.2 (but it is not correct as we don't know about axes).
Hence, the correct option is (a) "We cant tell without knowing what was plotted on the horizontal and vertical axes"
Work done = force x distance
= 2500 N x 2.5
= 6,250 Joules of work done.
