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2 years ago

How is the brightness of the star related to how quickly it pulses?

Physics

1 answer:

vladimir1956 [14]2 years ago

3 0

Answer:

The greater the luminosity of a star, the longer its period of oscillation.

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What is the velocity of an object that has a momentum of 4,000 kg-m/s and a mass of 115 kg? Round to the nearest hundredth.

julia-pushkina [17]

<h2>Answer: 34.78 m/s</h2>

Explanation:

The momentum $p$ is given by the following equation:

$p=m.V$ (1)

Where:

$m$ is the mass of the object

$V$ is the velocity of the object

Finding the velocity from (1):

$V=\frac{p}{m}$ (2)

$V=\frac{4000kg.m/s}{115kg}$

Finally:

$V=34.78m/s$ >>>This is the velocity of the object

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3 years ago

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Since acids are so corrosive they are not found anywhere in the human body true/false

pantera1 [17]

the answer is in fact True

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3 years ago

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A cell phone is released from the top with the speed of 10ms what is the speed 3s after?

sergeinik [125]

Answer:

30ms

Explanation:

you need to multiple the 10ms by 3s which gives you 30ms

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3 years ago

Using energy considerations, calculate the average force (in N) a 67.0 kg sprinter exerts backward on the track to accelerate fr

Illusion [34]

Answer:

$F_{sprinter}=110.4N$

Explanation:

Given data

Mass m=67.0 kg

Final Speed vf=8.00 m/s

Initial Speed vi=2.00 m/s

Distance d=25.0 m

Force F=30.0 N

From work-energy theorem we know that the work done equals the change in kinetic energy

W=ΔK=Kf-Ki=1/2mvf²-1/2mvi²

And

$W=F_{total}.d$

$W=1/2mv_{f}^2-1/2mv_{i}^2\\F_{total}=\frac{1/2mv_{f}^2-1/2mv_{i}^2}{d} \\F_{total}=\frac{1/2(67.0kg)(8.00m/s)^2-1/2(67.0kg)(2.00m/s)^2}{25.0m} \\F_{total}=80.4N$

and we know that the force the sprinter exerted Fsprinter the force of the headwind Fwind=30.0N

$F_{sprinter}=F_{total}+F_{wind}\\F_{sprinter}=80.4N+30N\\F_{sprinter}=110.4N$

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3 years ago

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By what factors does the speed of the elctron exceed that of the proton?

____ [38]

Answer:

» An electron is lighter than a proton.

explanation:

${ = \: \sf{an \: electron \: has \: formula \: \: }}{ \bf{ {}^{0}_{ - 1}e }}$

hence it's mass number is zero

${ = \: \sf{an \: electron \: is \: helium \: particle \: \: }}{ \bf{ {}^{4} _{2}He }}$

hence it's mass number is 4

Therefore, proton is heavier than electron

» An electron has a small charge magnitude than a proton.

Explanation:

An electron has charge of -1 while proton has charge of +2, therefore electron is less deflected by any energetic fields than a proton

8 0

3 years ago

How is the brightness of the star related to how quickly it pulses?​

How is the brightness of the star related to how quickly it pulses?