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The margin of error of the random selection is 0.29
The given parameters are:
--- the sample size
--- the standard deviation
--- the mean
--- the confidence level.
The margin of error (E) is calculated as follows:
So, we have:
The z-value for 90% confidence level is 1.645.
Substitute 1.645 for z
Take square roots
Multiply
Approximate
Hence, the margin of error is 0.29
Read more about margin of error at:
To find out the answer we divide 0.09 by 10: 
÷10=0.009.
Therefore, 0.09 is 10 times as much as 0.009.