Answer:
Area = (a² -5a) in²
Perimeter = (4a -10) in
Step-by-step explanation:
Let the length of the rectangle be a.
Given that, its width is 5 in less than the length.
So,
length ⇒ a
width ⇒ (a - 5)
First, let's find the area of the rectangle.
Area = length × width
Area = a ( a - 5 )
<em>Solve the brackets.</em>
Area = <u>(a² -5a) in²</u>
<u />
Now, let us find the perimeter of the rectangle.
Perimeter = 2 ( l + w )
Perimeter = 2 ( a + a - 5 )
Perimeter = 2 ( 2a - 5 )
Perimeter = <u>(4a -10) in</u>
Answer:
(1/2)
Step-by-step explanation:
The shape shrink in size by a factor of 2. So the answer is (1/2)
Check the picture below.
since in a rhombus the diagonals bisect each other, thus EC = EA.
now, the rhombus is simply 4 congruent triangles, we know the base and height of one of them, thus
![\bf \textit{area of a triangle}\\\\ A=\cfrac{1}{2}bh~~ \begin{cases} b=8\\ h=15 \end{cases}\implies A=\cfrac{1}{2}(8)(15)\implies A=60 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of all 4 triangles}}{4(60)\implies 240}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20triangle%7D%5C%5C%5C%5C%20A%3D%5Ccfrac%7B1%7D%7B2%7Dbh~~%20%5Cbegin%7Bcases%7D%20b%3D8%5C%5C%20h%3D15%20%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B1%7D%7B2%7D%288%29%2815%29%5Cimplies%20A%3D60%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7Barea%20of%20all%204%20triangles%7D%7D%7B4%2860%29%5Cimplies%20240%7D)
