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garik1379 [7]
3 years ago
6

If a regular polygon has 72 sides and an order of 72,what is the polygon’s rotational angle?

Mathematics
1 answer:
Misha Larkins [42]3 years ago
7 0

Answer:

The rotational angle of a regular polygon with 72 sides is 5º.

Step-by-step explanation:

The rotational angle (\theta), measured in sexagesimal degrees, of polygon of n sides is the angle of a complete revolution divided by the number of sides (n). That is:

\theta = \frac{360}{n} (1)

If we know that n = 72, the rotational angle is:

\theta = \frac{360}{72}

\theta = 5^{\circ}

The rotational angle of a regular polygon with 72 sides is 5º.

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The force acting on a beam was measured 5 times under the same operating conditions. This process was repeated by 3 observers, r
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The Pooled Standard Deviation for these data sets is 1.09

Step-by-step explanation:  

Given that;

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Standard Deviation 2 = 0.99

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pooled standard deviation is given as;

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where n1, n2....., nk are the sample sizes of k groups and s1, s2, ....., sk are the standard deviations of k groups respectively

so for the 3 groups;

S_{pooled}² =   (n1 - 1 )s1² + (n2 - 1 )s2² + ( n3 - 1)s3² / n1 + n2 + n3 - 3

we substitute

S_{pooled}² =   (5 - 1 )1.11² + (5 - 1 )0.99 ² + ( 5 - 1)1.15² / 5 + 5 + 5 - 3

S_{pooled}² =   (4.9284 + 3.9204 + 5.29) / 12

S_{pooled}² =   14.1388 / 12

S_{pooled}² =   1.1782

S_{pooled} = √1.1782

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28-2(4^2*4)

28 - 2 (4*4*4)

28-2(64)

28 -128 = 100

5 0
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