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3 years ago

If a regular polygon has 72 sides and an order of 72,what is the polygon’s rotational angle?

Mathematics

1 answer:

Misha Larkins [42]3 years ago

7 0

Answer:

The rotational angle of a regular polygon with 72 sides is 5º.

Step-by-step explanation:

The rotational angle ( $\theta$ ), measured in sexagesimal degrees, of polygon of $n$ sides is the angle of a complete revolution divided by the number of sides ( $n$ ). That is:

$\theta = \frac{360}{n}$ (1)

If we know that $n = 72$ , the rotational angle is:

$\theta = \frac{360}{72}$

$\theta = 5^{\circ}$

The rotational angle of a regular polygon with 72 sides is 5º.

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The perimeter of a rectangle is 30 in. if its lenth is 3 times the width, find the deminsions

MAXImum [283]

Step-by-step explanation:

2w+3(2w)=30

8w=30

w=3.75

l=11.25

7 0

3 years ago

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x) = 6x(1/3) + 3x(4/3). You must justi

stealth61 [152]

Applying our power rule gets us our first derivative,

$\rm f'(x)=6\frac13x^{-2/3}+3\cdot\frac43x^{1/3}$

simplifying a little bit,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

looking for critical points,

$\rm 0=2x^{-2/3}+4x^{1/3}$

We can apply more factoring.
I hope this next step isn't too confusing.
We want to factor out the smallest power of x from both terms,
and also the 2 from each.

$0=2x^{-2/3}\left(1+2x\right)$

When you divide x^(-2/3) out of x^(1/3),
it leaves you with x^(3/3) or simply x.

Then apply your Zero-Factor Property,

$\rm 0=2x^{-2/3}\qquad\qquad\qquad 0=(1+2x)$

and solve for x in each case to find your critical points.

Apply your First Derivative Test to further classify these points. You should end up finding that x=-1/2 is an relative extreme value, while x=0 is not.

Let's come back to this,

$\rm f'(x)=2x^{-2/3}+4x^{1/3}$

and take our second derivative.

$\rm f''(x)=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Looking for inflection points,

$\rm 0=-\frac43x^{-5/3}+\frac43x^{-2/3}$

Again, pulling out the smaller power of x, and fractional part,

$\rm 0=-\frac43x^{-5/3}\left(1-x\right)$

And again, apply your Zero-Factor Property, setting each factor to zero and solving for x in each case. You should find that x=0 and x=1 are possible inflection points.

Applying your Second Derivative Test should verify that both points are in fact inflection points, locations where the function changes concavity.

8 0

3 years ago

Marla helped her mother and father fold invitations and put them into envelopes. If Marla can fill 36 envelopes in 30 minutes, h

statuscvo [17]

Answer:

40 minutes

Step-by-step explanation:

12 envelopes every 10 minutes.

48 envelopes = 40 minutes

3 0

2 years ago

Read 2 more answers

What is the correct answer?

Leno4ka [110]

Answer:

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate

Harman [31]

Answer:

Yes

Step-by-step explanation:

Given that Machine M, working alone at its constant rate, produces x widgets every 4 minutes. Machine N, working alone at its constant rate, produces y widgets every 5 minutes.

When both machines work for 20 minutes

Machine A would produce = $\frac{20}{4} =5$ widget and

Machine B would produce = $\frac{20}{5} =4$ widgets

So we can say that Machine A would produce more widgets than Machine N at that time.

Answer is Yes

8 0

3 years ago