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Greeley [361]
3 years ago
6

What is the density of a 25.8 g piece of broken glass that has a volume of 10.3 cm cubed

Chemistry
1 answer:
anygoal [31]3 years ago
4 0

Answer:

2.5

Explanation:

d=m/v

d=25.8÷10.3

d=2.5048543689

d=2.5

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Which organism on the food chain is a carnivore? fungus grass grasshopper spider
Lady_Fox [76]

Answer:

I think it would it spider

Explanation:

Spider catch there meals in there web then suck the blood out after it wraps them up in webing

5 0
3 years ago
Student Exploration: Limiting Reactants Vocabulary: chemical equation, chemical formula, chemical reaction, coefficient, limitin
SIZIF [17.4K]

Answer:

30 hot dogs

Explanation:

It is given that :

There are 4 packets of eight wieners, i.e. 4 x 8 = 32 wieners

There are 3 bags of ten buns, i.e. 3 x 10 = 30 buns

One hot dogs need 1 bun and 1 wiener to make a hot dog.

There are 30 buns, so 30 hot dogs can be made out by using all the 30 buns and the 30 wieners out of the 32 wieners.

Therefore, 30 hot dogs.

And the number of extra wieners left = 32 - 30 = 2 wieners.

6 0
2 years ago
Describe what happens when ice changes<br> into liquid water.
chubhunter [2.5K]

Answer:

When ice changes into liquid water it melts. The solidified ice in the frozen, would melt via the burning sun shooting its streaks down at the ice. Which causes the ice to melt, and turn into liquid water.

Explanation:

pp poopoo

3 0
3 years ago
What does climate change have to do with glacial change ​
qwelly [4]

Answer:

Because glaciers are so sensitive to temperature fluctuations accompanying climate change. so if it gets hotter then the ice glaciers will melt.

Explanation:

3 0
3 years ago
A gas has a volume of 1.75L at -23°C and 150.0 kPa. At what temperature would the gas occupy 1.30L at 210.0 kPa?
Nastasia [14]

Answer:

At -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

Explanation:

Let's assume the gas behaves ideally.

As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-

                                          \frac{P_{1}V_{1}}{T_{1}}=\frac{P_{2}V_{2}}{T_{2}}

where P_{1} and P_{2} are initial and final pressure respectively.

           V_{1}  and V_{2} are initial and final volume respectively.

           T_{1} and T_{2} are initial and final temperature in kelvin scale respectively.

Here P_{1}=150.0kPa , V_{1}=1.75L , T_{1}=(273-23)K=250K, P_{2}=210.0kPa and V_{2}=1.30L

Hence    T_{2}=\frac{P_{2}V_{2}T_{1}}{P_{1}V_{1}}

            \Rightarrow T_{2}=\frac{(210.0kPa)\times (1.30L)\times (250K)}{(150.0kPa)\times (1.75L)}

            \Rightarrow T_{2}=260K

            \Rightarrow T_{2}=(260-273)^{0}\textrm{C}=-13^{0}\textrm{C}

So at -13 ^{0}\textrm{C} , the gas would occupy 1.30L at 210.0 kPa.

5 0
3 years ago
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