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Greeley [361]
3 years ago
6

What is the density of a 25.8 g piece of broken glass that has a volume of 10.3 cm cubed

Chemistry
1 answer:
anygoal [31]3 years ago
4 0

Answer:

2.5

Explanation:

d=m/v

d=25.8÷10.3

d=2.5048543689

d=2.5

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What is the initial temperature (°C) of a system that has the pressure decreased by 10 times while the volume increased by 5 tim
Ede4ka [16]

Answer:

300K

Explanation:

Given pressure of the system decreased by 10 times which means P_{2} =\frac{P_{1} }{10}

Given the volume of the system increased by 5 times which means V_{2} =5\times V_{1}

Given final temperature T_{2}=150K

Let the initial temperature be T_{1}

We know that PV=nRT

As n and R are constant \frac{PV}{T}=constant

\frac{P_{1}V_{1} }{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}

T_{1} =\frac{P_1V_1}{P_2V_2} T_{2}

T_{1} =2\times T_{2}

T1=300K

8 0
3 years ago
What challenges would you encounter with the titration if you had used apple cider vinegar or balsamic vinegar as the analyte in
Vika [28.1K]

Explanation:

Apple cider vinegar or balsamic vinegar might contain various synthetics which might  interact with or nullified the findings, whereas white vinegar comprises of acidic acid only. In fact, apple cider vinegar and balsamic vinegar are deep in appearance this would make it very difficult to determine the color. This is why it is preferable to use white vinegar in the Titration process.

3 0
3 years ago
A tire at 21°C has a pressure of 0.82 atm. Its temperature decreases to –3.5°C. If there is no volume change in the tire, what i
Damm [24]

The correct answer is A 0.75 atm


4 0
3 years ago
Read 2 more answers
29. What is E for a system which has the following two steps:
jasenka [17]

Answer:

Zero

Explanation:

Recall that;

E = q + w

Where;

q = heat, w = work done

When heat is absorbed by the system q is positive

When heat is evolved by the system q is negative

When the system does work, w is negative

When work is done on the system w is positive

Step 1

ΔE1= 60 KJ + 40 KJ = 100KJ

Step 2

ΔE2= (-30 KJ) + (-70 KJ) = (-100) KJ

ΔE1 + ΔE2= 100KJ + (-100) KJ = 0KJ

4 0
3 years ago
A hypothetical element, E, has two stable isotopes. One isotope has a natural abundance of 68.037% and has an atomic mass of 46.
I am Lyosha [343]
  • If the abundance of the first isotope is 68.037%, then the abundance of the second isotope is 100%-68.037%.

Substituting into the atomic mass formula,

47.574=(46.449)(0.68037)+x(1-0.68037)\\\\ 47.574=31.60250613+0.31963x\\\\15.97149387=0.31963x\\\\x \approx \boxed{49.969 \text{ u}}

6 0
2 years ago
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