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mamaluj [8]
3 years ago
7

15.Can someone help me?​

Mathematics
1 answer:
Elina [12.6K]3 years ago
6 0

Answer:

The radius, in inches, of the base of the cone will be:

r = 6 inches

Hence, option B is correct.

Step-by-step explanation:

Given

The Volume of a right circular cone V = 24 π cubic inches

The height of the cone h = 2 inches

To determine

The radius of the base of the cone r = ?

Using the formula involving Volume m, height h, and radius r of a right circular cone.

V\:=\frac{1}{3}h\:\pi \:\:r^2\:

substituting V = 24 π, h = 2 to find the radius r

\left(24\pi \right)=\frac{1}{3}\left(2\right)\:\pi \:r^2

switch sides

\frac{1}{3}\left(2\right)\pi r^2=\left(24\pi \right)

\frac{1}{3}2\pi r^2=24\pi

simplify

2\pi r^2=72\pi

Divide both sides by 2π

\frac{2\pi r^2}{2\pi }=\frac{72\pi }{2\pi }

r^2=36

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

r=\sqrt{36},\:r=-\sqrt{36}

Thus,

r=6,\:r=-6

As we know that the radius can not be negative.

Therefore, the radius, in inches, of the base of the cone will be:

  • r = 6 inches

Hence, option B is correct.

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Circumference of the cylinder a cylinder of the base with the diameter of 6cm and height of 12cm
yuradex [85]

Answer:

To find the volume, we must find the area of the circle and multiply it by its height, think of a cylinder as an object made up of MANY circles. So, V=pir^2h... so diameter is 6cm so radius = 3cm...

therefore, Volume = (pi)(3^2)(12) = 108(pi)

where 12 = height 3 = radius

For the surface area, we need to find the area of the 2 circles(top and bottom ) so once again,

2(pi)(r^2) = 2(pi)(9)

for the area of the rectangle(if we unfold the cylindrical can) we get D(pi)(12) where D= Diameter

so the surface area is

SA = (2)(9)(pi) + 6(pi)(12)

SA = 18pi + 72pi = 90pi

7 0
2 years ago
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zepelin [54]

Answer:

4 equals 1 is the answer

Step-by-step explanation:

8 0
2 years ago
One positive number is one-fifth of another number. the difference of the two numbers is 84. find the numbers.
seraphim [82]
Answer:  The numbers are:  " 21 " and " 105 " .
___________________________________________________
Explanation:
___________________________________________________
Let "x" be the "one positive number:

Let "y" be the "[an]othyer number".

x = 1/5 (y)
___________________________________________________
Given that the difference of the two number is "84" ;  and that "x" is (1/5) of  "y" ;  we determine that "x" is smaller than "y".

So, y − x = 84 .

Add "x" to each side of this equation; to solve for "y" in terms of "x" ;

y − x + x = 84 + x  ;

 y = 84 + x ;
___________________________________________________
So, we have: 

 x = (1/5) y ;

and:  y = 84 + x  ;

Substitute "(1/5)y" for "x" ;  in  "y = 84 + x " ;  to solve for "y" ;

 y = 84 + [ (1/5)y ]

Subtract  " [ (1/5)y ] " from EACH SIDE of the equation ;

y − [ (1/5)y ] = 84 + [ (1/5)y ] −  [ (1/5)y ]  ;

to get:

  [ (4/5)y ] = 84 ;


       ↔    (4y) / 5 = 84  ;
      
        →  4y = 5 * 84  ;

      Divide EACH SIDE of the equation by "4" ; 
to isolate "y" on one side of the equation; and to solve for "y" ;

           4y / 4 = (5 * 84) / 4 ;

                 y =  5 * (84/4) = 5 * 21 = 105 .

   y = 105 .
___________________________________________________
Now, plug "105" for "y" into:
___________________________________________________
Either:
___________________________________________________
 x = (1/5) y ;

OR:

  y = 84 + x  ;
___________________________________________________
to solve for "x" ;
___________________________________________________
Let us do so in BOTH equations; to see if we get the same value for "x" ; which is a method to "double check" our answer ;
___________________________________________________
Start with:

x = (1/5)y 

    →  (1/5)*(105) = 105 / 5 = 21 ;  x = 21 ; 

___________________________________________________
So, x = 21;  y = 105 .
___________________________________________________
Now, let us see if this values hold true in the other equation:
___________________________________________________
y = 84 + x ;

105 = ? 84 + 21 ?
 
105 = ? 105 ? Yes!
___________________________________________________
The numbers are:  " 21 " and  "105 " .
___________________________________________________

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The corresponding formula would of course be 

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<span>as noted above.</span>
4 0
3 years ago
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