Answer:
7x-48
Step-by-step explanation:
we want our equation to look something like this
y=mx+b
let's start by solving for m (the slope) using the slope formula
Which means, so far, our equation looks like this
y=7x+b
now we just need to solve for B
We can do this by plugging in a set of coordinates
-6=7*6+b
-6=42+b
-48=b
which means our equation is
7x-48
<u>ANSWER: </u>
If a ball is thrown into the air with a velocity of 34 feet per second, then velocity of the ball after 1 second is 2 feet per second
<u>SOLUTION: </u>
Given, a ball is thrown into the air with a velocity of 34 feet per second
Initial velocity (u) = 34 feet per second
And also given a relation between displacement and time = --- eqn 1
We need to find the velocity when t = 1 ; v = ?
We know that, v = u + at and
where v is instantaneous velocity and u is initial velocity
a is acceleration
t is time interval
s is displacement
using the displacement and time relation eqn (1) we get
Now, when t = 1, displacement s = 34(1) – 16(1)
here, -ve sign indicates that object is in deceleration . so acceleration is -32 ft/s
now put a value in v = u + at
v = 34 + (-32)(1)
v = 34 – 32
v = 2 ft/s
Hence, velocity of the ball after 1 second is 2 ft/s