Answer:
![73 in.^2](https://tex.z-dn.net/?f=73%20in.%5E2)
Step-by-step explanation:
The figure shown here consists of two pieces:
- A hemicircle
- A triangle
So, the total area of the figure is the sum of the areas of the two parts.
The area of the hemicircle is given by:
![A_1=\frac{\pi r^2}{2}](https://tex.z-dn.net/?f=A_1%3D%5Cfrac%7B%5Cpi%20r%5E2%7D%7B2%7D)
where
r = 4 in. is the radius (half the diameter, which is 8 inches)
Therefore,
![A_1=\frac{\pi (4)^2}{2}=25.1 in.^2](https://tex.z-dn.net/?f=A_1%3D%5Cfrac%7B%5Cpi%20%284%29%5E2%7D%7B2%7D%3D25.1%20in.%5E2)
The area of the triangle is given by
![A_2=\frac{1}{2}bh](https://tex.z-dn.net/?f=A_2%3D%5Cfrac%7B1%7D%7B2%7Dbh)
where
b is the base
h is the height
Here we have:
h = 8 in. is the height
The base is the total length (16 in.) minus the radius of the circle, so
![b=16 - 4 = 12 in.](https://tex.z-dn.net/?f=b%3D16%20-%204%20%3D%2012%20in.)
So the area of the triangle is
![A_2=\frac{1}{2}(12)(8)=48 in.^2](https://tex.z-dn.net/?f=A_2%3D%5Cfrac%7B1%7D%7B2%7D%2812%29%288%29%3D48%20in.%5E2)
So the total area of the figure is
![A=A_1+A_2=25 in^2 + 48 in^2 = 73 in.^2](https://tex.z-dn.net/?f=A%3DA_1%2BA_2%3D25%20in%5E2%20%2B%2048%20in%5E2%20%3D%2073%20in.%5E2)
The Last answer is correct. For math problems i suggest photo math for cellular devices.
Answer:
8
Step-by-step explanation:
7x+y=0
x+6y=5
x-y+4=8
Answer: x^2+9x+20
Step-by-step explanation:
To find the area you multiply the sides so it should be (x+4)(x+5) which is x^2+9x+20. Good luck!