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2 years ago

Which choice is equivalent to the quotient shown here when x>0?

Mathematics

1 answer:

shutvik [7]2 years ago

7 0

Answer:

The answer to your question is letter C.

Step-by-step explanation:

$\sqrt{50x^{3}}$ Find the prime factors of 50

50 2

25 5

5 5

50 = 2 5²

$\sqrt{5^{2} 2 x^{2} x} = 5 x\sqrt{2x}$

$\sqrt{32x^{2}}$ Find the prime factors of 32

32 2

16 2

8 2

4 2

2 2

32 = 2⁴2 $\sqrt{32x^{2}} = 2^{2} x\sqrt{2} = 4x\sqrt{2}$

Division $5x\sqrt{2}\sqrt{x} / 4x\sqrt{2}$

Simplification $\frac{5\sqrt{x}}{4}$

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2 years ago

If x equals 5 what is 72+72+18x+9+18x+9

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Answer:

342

Step-by-step explanation:

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2 years ago

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3 years ago

HELP ASAP : Find the largest value of n such that 5x^2+nx+48 can be factored as the product of two linear factors with integer c

Anna71 [15]

Answer:

$n=241$

Step-by-step explanation:

We are given

$5x^2+nx+48$

Let's assume it can be factored as

$5x^2+nx+48=(5x-s)(x-r)$

now, we can multiply right side

and then we can compare it

$5x^2+nx+48=5x^2-5rx-sx+rs$

$5x^2+nx+48=5x^2-(5r+s)x+rs$

now, we can compare coefficients

$rs=48$

$5r+s=-n$

$n=-(5r+s)$

now, we can find all possible factors of 48

and then we can assume possible prime factors of 48

$48=-+(1\times 48)$

$48=-+(2\times 24)$

$48=-+(3\times 16)$

$48=-+(4\times 12)$

$48=-+(6\times 8)$

Since, we have to find the largest value of n

So, we will get consider larger value of r because of 5r

and because n is negative of 5r+s

so, we will both n and r as negative

So, we can assume

r=-48 and s=-1

so, we get

$n=-(5\times -48-1)$

$n=241$

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3 years ago