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3 years ago

Write an equation that models the linear relationship in the table.

Mathematics

1 answer:

hjlf3 years ago

8 0

Answer:

C. y = -3x + 4

Step-by-step explanation:

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Y = 4x – 10 y = 2 what is the solution to the system of equations? (3, 2) (2, 3) (–2, 2) (2, –2)

Scilla [17]

Y = 2

y = 4x - 10
2 = 4x - 10
2 + 10 = 4x
12 = 4x
12/4 = x
3 = x

solution is : (3,2)

4 0

3 years ago

Read 2 more answers

I need help with this assignment.

Gelneren [198K]

2. Definition of supplementary angles
I’m not too good with proofs but hopefully at least one answer helped lol sorry

8 0

3 years ago

Divide 12x 4 y 4 by 3x 2 y. A. 4x 6y 5 B. 4x 2y 3 C. 9x 6 D. 9x 2y 3

andrew-mc [135]

Answer:

$\frac{12x^4y^4}{3x^2y}=4x^2y^3$

Step-by-step explanation:

Consider an element $a\neq 0$

We know that $\frac{a^m}{a^n}=a^{m-n}$

Here, m and n are exponents and a is a base. Exponent refers to the no. of times a term is multiplied by itself. Another word for exponents is powers.

Other Properties of exponents:

$a^m\times a^n=a^{m+n}\\a^0=1\\\left ( a^m \right )^n=a^{mn}$

Here, we are required to divide $12x^4y^4$ by $3x^2y$ .

Consider $\frac{12x^4y^4}{3x^2y}$

We will solve $\frac{12}{3}\,,\,\frac{x^4}{x^2}\,,\,\frac{y^4}{y}$ separately.

Here,

$\frac{12}{3}=4\\\frac{x^4}{x^2}=x^{4-2}=x^2\\\frac{y^4}{y}=y^3$

So, $\frac{12x^4y^4}{3x^2y}=4x^2y^3$

8 0

3 years ago

How do I solve -5 - (15y - 1) = 2 (7y - 16) - y

Aleks [24]

If you want to solve the equation -5 - (15 * y - 1) = 2 * (7 * y - 16) - y, you can calculate this using the following steps:

-5 - (15 * y - 1) = 2 * (7 * y - 16) - y
-5 - 15 * y + 1 = 14 * y - 32 - y
-5 + 1 + 32 = 14 * y - y + 15 * y
28 = 28 * y /28
y = 1

The result is 1.

6 0

3 years ago

39.2 is 95 percent of what?

snow_tiger [21]

267 is what the answer is sorry if it’s wrong

4 0

3 years ago