Answer:
air is a group of different gases and gas is loose bound atoms of an element
Explanation:
Answer:
The answer to your question is 100.8 g
Explanation:
Data
mass of Barium chloride = 90 g
mass of Barium sulfate = ?
Balanced chemical reaction
BaCl₂ + H₂SO₄ ⇒ BaSO₄ + 2HCl
Process
1.- Calculate the molar mass of BaCl₂ and BaSO₄
BaCl₂ = 137.3 + (2 x 35.5) = 208.3g
BaSO₄ = 137.3 + 32 + (16 x 4) = 233.3g
2.- Use proportions to find the mass of BaSO₄
208.3 g of BaCl₂ --------------------- 233.3 g of BaSO₄
90 g of BaCl₂ --------------------- x
x = (90 x 233.3) / 208.3
x = 20997/ 208.3
x = 100.8 g
3.- Conclusion
There will be produced 100.8 g of BaSO₄
Answer: 8.33 mol of HCl (Hydrochloric Acid)
Explanation:
150 g H2O x __1 mol__ x __1 mol HCl__ = 8.33 mol of HCl
18.016 g 1 mol H2O
Answer:
The age of the sample is 4224 years.
Explanation:
Let the age of the sample be t years old.
Initial mass percentage of carbon-14 in an artifact = 100%
Initial mass of carbon-14 in an artifact = ![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
Final mass percentage of carbon-14 in an artifact t years = 60%
Final mass of carbon-14 in an artifact = ![[A]=0.06[A_o]](https://tex.z-dn.net/?f=%5BA%5D%3D0.06%5BA_o%5D)
Half life of the carbon-14 = 

![[A]=[A_o]\times e^{-kt}](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA_o%5D%5Ctimes%20e%5E%7B-kt%7D)
![[A]=[A_o]\times e^{-\frac{0.693}{t_{1/2}}\times t}](https://tex.z-dn.net/?f=%5BA%5D%3D%5BA_o%5D%5Ctimes%20e%5E%7B-%5Cfrac%7B0.693%7D%7Bt_%7B1%2F2%7D%7D%5Ctimes%20t%7D)
![0.60[A_o]=[A_o]\times e^{-\frac{0.693}{5730 year}\times t}](https://tex.z-dn.net/?f=0.60%5BA_o%5D%3D%5BA_o%5D%5Ctimes%20e%5E%7B-%5Cfrac%7B0.693%7D%7B5730%20year%7D%5Ctimes%20t%7D)
Solving for t:
t = 4223.71 years ≈ 4224 years
The age of the sample is 4224 years.