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gtnhenbr [62]
3 years ago
5

In the chemical formula 2so2, how many total atoms of sulfur (s) are there? 1 2 4

Chemistry
1 answer:
babunello [35]3 years ago
6 0
Sulfur has the coefficient of 2, and nothing else. This indicates Sulfur has 2 atoms. 


<span>Oxygen on the other hand, has a subscript of 2, as well as the coefficient of 2. Multiplying those, and you see Oxygen has 4 atoms. 
</span>
So your answer is 2

Also remember there is a 2 in front of S meaning there are 2 Sulfurs. 
<span>If it was S02 it would be 1 Sulfur as there is no number in front of sulfer. </span>

<span>Remember the number in front of a element, represents how many atoms there are :)</span>
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Determine the temperature change when 150. G block of gold is supplied with 1.00 • 10 ^3 J of heat
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Answer:

∇T = 51.68°C

Explanation:

Mass = 150g

Heat Energy (Q) = 1.0*10³J

Change in temperature ∇T = ?

Q = mc∇T

Q = heat energy

M = mass

C = specific heat capacity of the gold = 0.129j/g°C

∇T = change in temperature

Q = Mc∇T

1.0*10³ = 150 * 0.129 * ∇T

1000 = 19.35∇T

Solve for ∇T

∇T = 1000 / 19.35

∇T = 51.679°C = 51.68°C

The change in temperature of gold was 51.68°C

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How many grams of magnesium<br> sulfate (MgSO4) are dissolved in<br> 0.965 L of a 0.0575 M solution?
JulsSmile [24]
<h3>Answer:</h3>

6.68 g MgSO₄

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Aqueous Solutions</u>

  • Molarity = moles of solute / liters of solution

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.965 L

0.0575 M

<u>Step 2: Identify Conversions</u>

Molar Mass of Mg - 24.31 g/mol

Molar Mass of S - 32.07 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of MgSO₄ - 24.31 + 32.07 + 4(16.00) = 120.38 g/mol

<u>Step 3: Find MgSO₄</u>

  1. Substitute [M]:                     0.0575 M = x / 0.965 L
  2. Isolate <em>x</em>:                              0.055488 mol MgSO₄ = x
  3. Rewrite:                               x = 0.055488 mol MgSO₄

<u>Step 4: Convert</u>

<u />\displaystyle 0.055488 \ mol \ MgSO_4(\frac{120.38 \ g \ MgSO_4}{1 \ mol \ MgSO_4} ) = 6.67959 g MgSO₄

<u>Step 5: Check</u>

<em>We are given 3 sig figs as our lowest. Follow sig fig rules and round.</em>

6.67959 g MgSO₄ ≈ 6.68 g MgSO₄

5 0
3 years ago
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