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2 years ago

Which of the following occurs when an electron moves from a higher energy shell to a lower energy shell?

Chemistry

2 answers:

Alekssandra [29.7K]2 years ago

7 0

Answer: Option (C) is the correct answer.

Explanation:

When energy is supplied to an electron then on absorption of energy it tends to move from a lower energy level to higher energy level.

And, when this electron moves from higher energy level to lower energy level then excess of energy absorbed by it is released in the form of visible light or radiation.

This emission of energy is also responsible for imparting color to a compound.

Thus, we can conclude that energy is released in the form of radiation occurs when an electron moves from a higher energy shell to a lower energy shell.

enot [183]2 years ago

6 0

The answer would be C: energy is released to form radiation.

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Which is a chacteristic of a solution?

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A solution is a homogeneous mixture of two or more substances. The particles of solute in a solution cannot be seen by the naked eye. A solution does not allow beams of light to scatter.

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3 years ago

1. Using the Hoffman apparatus for electrolysis, a chemist decomposes 50.5 g of water into its gaseous elements. How many grams

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3 years ago

Why does a catalyst work for a long time before it needs replacing?

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3 years ago

a scientist uses 68 grams of CaCo3 to prepare 1.5 liters of solution. what is the molarity of this solution?

victus00 [196]

Answer: 0.4533mol/L

Explanation:

Molar Mass of CaCO3 = 40+12+(16x3) = 40+12+48 = 100g/mol

68g of CaCO3 dissolves in 1.5L of solution.

Xg of CaCO3 will dissolve in 1L i.e

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3 years ago

A gas stream containing n-hexane in nitrogen with a relative saturation of 0.58 (as a fraction, multiply by 100% if you prefer %

kondor19780726 [428]

This problem is describing a gas mixture whose mole fraction of hexane in nitrogen is 0.58 and which is being fed to a condenser at 75 °C and 3.0 atm, obtaining a product at 3.0 atm and 20 °C, so that the removed heat from the system is required.

In this case, it is recommended to write the enthalpy for each substance as follows:

$H_{C-6}=y_{C-6}C_v(T_b-Ti)+\Delta _vH+C_v(T_f-Tb)\\\\H_{N_2}=y_{N_2}C_v(T_f-Ti)$

Whereas the specific heat of liquid and gaseous n-hexane are about 200 J/(mol*K) and 160 J/(mol*K) respectively, its condensation enthalpy is 31.5 kJ/mol, boiling point is 69 °C and the specific heat of gaseous nitrogen is about 29.1 J/(mol*K) according to the NIST data tables and $y_{C-6}$ and $y_{N_2}$ are the mole fractions in the gaseous mixture. Next, we proceed to the calculation of both heat terms as shown below:

$H_{C-6}=0.58*200(69-75)+(-31500)+160(20-69)=-40036J/mol\\\\H_{N_2}=0.42*29.1(20-75)=-672.21J/mol$

It is seen that the heat released by the nitrogen is neglectable in comparison to n-hexanes, however, a rigorous calculation is being presented. Then, we add the previously calculated enthalpies to compute the amount of heat that is removed by the condenser:

$Q=-40036+(-672.21)=-40708.21J$

Finally we convert this result to kJ:

$Q=-40708.21J*\frac{1kJ}{1000J}\\\\Q=-40.7kJ$

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2 years ago