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Ilya [14]
3 years ago
13

Solve the following system of equations by substitution and select the correct answer below:

Mathematics
2 answers:
Anni [7]3 years ago
6 0
The answer is x= 4 and y= -3

6x-4y=36 -- (1)

2x-8y=32- (2)

from (1)
-4y= 36-6x
y= -9+3/2x 

(3) into (2)
2x-8(-9+3/2x)=32
2x+72-12x=32
72-10x=32
-10x= -40
x= 4

sub x=4 into y= -9+3/2x
y= -9+3/2(4)
y= -3
Sauron [17]3 years ago
3 0
First, we take one of our equations and solve for one variable in terms of the other.
This is similar to solving a one-variable equation.

6x - 4y = 36
Get one variable on one side.
6x = 36 + 4y
Divide by 6.
x = 6 + 2/3y

Now, we substitute this value for x in our second equation.

2x - 8y = 32
2(6 + 2/3y) - 8y = 32
Distribute the 2...
12 + 4/3y - 8y = 32
Subtract 12 from each side...
4/3y - 8y = 20
Multiply everything by 3 to get rid of that fraction.
4y - 24y = 60
-20y = 60
Divide by -20...
y = -3

Use this value in an earlier equation to find x.

<span>6x − 4y = 36
</span>6x - 4(-3) = 36
6x + 12 = 36
6x = 24
x = 4
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Simplify: (2x - 4) - (6x + 6)
tatiyna

<h3>(2x - 4) - (6x + 6) = -2( 2x + 5 )</h3>

<h3>Further explanation</h3>

Order of Operations in Mathematics follow this following rule :

  1. Parentheses
  2. Exponents
  3. Multiplication and Division
  4. Addition and Subtraction

This rule is known as the PEMDAS method.

Let us tackle the problem!

(2x - 4) - (6x +6) = 2x - 4 - 6x - 6 ⇒ open parenthesis

(2x - 4) - (6x +6) = 2x - 6x - 4 - 6 ⇒ rearrange term

(2x - 4) - (6x +6) = (2 - 6)x - 10 ⇒ factorize

(2x - 4) - (6x +6) = -4x - 10

\large {\boxed {(2x - 4) - (6x +6) = -2( 2x + 5 ) } }

<h2>Another Example :</h2>

(2x - 4) + (6x +6) = 2x - 4 + 6x + 6 ⇒ open parenthesis

(2x - 4) + (6x +6) = 2x + 6x - 4 + 6 ⇒ rearrange term

(2x - 4) + (6x +6) = (2 + 6)x + 2 ⇒ factorize

(2x - 4) + (6x +6) = 8x + 2

\large {\boxed {(2x - 4) + (6x +6) = 2( 4x + 1 ) } }

<h3>Learn more</h3>
  • Infinite Number of Solutions : brainly.com/question/5450548
  • System of Equations : brainly.com/question/1995493
  • System of Linear equations : brainly.com/question/3291576

<h3>Answer details</h3>

Grade: High School

Subject: Mathematics

Chapter: Linear Equations

Keywords: Linear , Equations , 1 , Variable , Line , Gradient , Point

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