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Andrew [12]
4 years ago
15

The half-life of caffeine is 5 hours. If you ingested a 30 oz Big Gulp, how many oz of caffeine is left after one half life? * Y

our answer
Physics
1 answer:
xeze [42]4 years ago
8 0

Answer:

The amount of caffeine left after one half life of 5 hours is 15 oz.

Explanation:

Half life is the time taken for a radioactive substance to degenerate or decay to half of its original size.

The half life of caffeine is 5 hours. So ingesting a 30 oz, this would be reduced to half of its size after the first 5 hours.

So that:

After one half life of 5 hours, the value of caffeine that would be left is;

                                    \frac{30}{2} = 15 oz

The amount of caffeine left after one half life of 5 hours is 15 oz.

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An ammeter is connected in series with a resistor of unknown resistance R and a DC power supply of known emf e. A student uses t
rosijanka [135]

Answer:

B:The actual power dissipated by the resistor is less than P because the ammeter had some resistance.

Explanation:

Here,power has been calculated using current I and total EMF \ε . So,P=EMF*current= ε I will represent total power dissipated in resistor and ammeter.

Now, this total power P has been dissipated in both resistor and ammeter. So, power dissipated in resistor must be less than P as some power is also dissipated in ammeter because it has non-zero resistance.

So, the answer is B:The actual power dissipated by the resistor is less than P because the ammeter had some resistance.

Note that option A,C and E are ruled out as they state power dissipated by resistor is greater than or equal to P which is false.

Also,option D is ruled out as ammeter is connected in series.

8 0
4 years ago
What is the velocity of a motercycle traveling 13 km west in 3 hours
Soloha48 [4]
4.333333 kilometers an hour
5 0
3 years ago
The speed of light in a vacuum is approximately 2.99 × 108 m/s, and the speed of light through a piece of glass is approximately
scoundrel [369]

Answer: Have A Blessed Day!

Explanation:

Thanks for the information mate!

(Also can I have brainliest i'm so close to next rank! Thanks and have a good life!)

3 0
3 years ago
A hummingbird 3.4m above the ground flies 1.2 m along a straight line path. Upon spotting a flower below, the hummingbird drops
Anit [1.1K]

A = horizontal displacement of the humming bird = 1.2 m

B = vertical displacement of the humming bird = 1.4 m

C = net displacement of the humming bird from initial to final position = ?

In the triangle drawn , Using Pythagorean theorem

C = √(A² + B²)

inserting the values

C = √(1.2² + 1.4²)

C = √(1.44 + 1.96)

C = √(3.4)

C = 1.4 m

Hence the net displacement of hummingbird comes out to be 1.4 m

4 0
3 years ago
Read 2 more answers
What is the speed of a 55.0 kg skydiver who has 7.81 x 104 J of kinetic energy?
KATRIN_1 [288]

Answer:

v=53.3m/s

Explanation:

Ek=1/2mv²

7.81×10⁴=1/2×55.0v²

v= the square root of 7.81×10⁴/0.5×55.0

v=53.3m/s

5 0
4 years ago
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