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patriot [66]
3 years ago
6

7. An automobile with a radio antenna 1.0 m long travels at 100.0 km/h in a location where the Earth’s horizontal magnetic field

is 5.5×10−5T. What is the maximum possible emf induced in the antenna due to this motion?
Physics
1 answer:
VashaNatasha [74]3 years ago
3 0

Answer:

0.00479 volts

Explanation:

From Faraday's law of electromagnetic induction, the induced emf equals the change in magnitude flux (magnetic field strength multiplied by the area = BA) divided by the time change

Therefore we have the equation

EMF = BA÷t

Since area A = 2πr

EMF = Bπr²÷t

B = 5.5×10^(-5)

Velocity = 100km/h = 27.7778m/s

r = 1m, t = r÷V = 0.036

EMF = Bπr²÷t = (5.5×10^(-5) x π x (1)²)÷0.036 = 0.00479 Volts

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What best describes the angle between a changing electric field and the electromagnetic wave produced by it?
MrRa [10]

The correct ans is 1.

A changing electric field produces a changing magnetic field which in turn produces a changing electric field. This means that the source has created a changing electric and magnetic fields, perpendicular to each other, that travel away from the source. Electric field, magnetic field and the EM wave are perpendicular to each other. This gives electromagnetic waves their transverse nature.

7 0
3 years ago
The Earth's atmosphere is opaque to the
Firdavs [7]
All of the above is correct
4 0
3 years ago
At a maximum level of loudness, the power output of a 75-piece orchestra radiated as sound is 72.0 W. What is the intensity of t
FrozenT [24]

Answer:

<em> The intensity would be 0.01432 W/</em>m^{2}<em></em>

Explanation:

The sound intensity is the power that is transmitted by a sound wave per unit area.

Given that

Power output P of the 75-piece orchestra = 72.0 W

The listener's distance  r = 20.0 m

The intensity of sound waves (I) can be obtained with the expression below;

I = P/A .............. 1

where P is the power

A is the area, in this case, at the distance r the sound is radiated through  a sphere.

A = area of a sphere = 4πr^{2}

putting it into equation 1, the intensity would be;

I = P/ 4πr^{2}

Substituting our values we have;

I = 72.0 W /  4 π 20^{2} m^{2}

I = 0.01432 W/m^{2}

Therefore the intensity would be 0.01432 W/m^{2}

3 0
3 years ago
Two points charges 34C,64C are separated by distance of 3cm , find the electric force?​
Misha Larkins [42]
I think it is 4 cm because if you look hard enough and work the problem the number pops in you head. Lol
4 0
3 years ago
"if a 20 and a 40 ohm resistor are wired in parallel to a 20v source, what will be the current in the 40 ohm resistor?"
choli [55]

In parallel, neither resistor knows about the other one, and they have no effect on each other.

Each resistor is connected straight to the battery terminals. If the battery is hefty enough, it supplies current to each resistor as if the other one weren't there.

Current through a resistor = (voltage across it) / (its resistance).

Current = (20 V) / (40 ohms)

Current = 1/2 Ampere.

4 0
3 years ago
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