Answer:
-0.64525g
Explanation:
t = Time taken for the car to stop
u = Initial velocity = 95 km/h
v = Final velocity = 0 km/h
s = Displacement
a = Acceleration
Equation of motion

Converting to m/s²

g = Acceleration due to gravity = 9.81 m/s²
Dividing both the accelerations, we get

Hence, acceleration of the car is -0.64525g
Velocidad-es una cantidad vectorial física; Tanto la magnitud como la dirección son necesarias para definirlo.
(B)Option b is your answer..........