52/72
13/18 is your answer. Therefore, C.
Answer:
1.U={1,2,3,4,5}
A={2}
B={2,3}
C={4,5}
2.U={1,2,3,4}
A={1,2}
B={2,3}
C={4}
Step-by-step explanation:
We are given that
and 
are different sets
1.We have to construct a universe set U and non empty sets A,B and C so that above set in fact the same
Suppose U={1,2,3,4,5}
A={2}
B={2,3}
C={4,5}

{2,3,4,5}
={2}
{2,3,4,5}={2}
={2}
={2}
Hence, 
2.We have to construct a universe set U and non empty sets A,B and C so that above sets are in fact different
Suppose U={1,2,3,4}
A={1,2}
B={2,3}
C={4}

={2,3,4}
={1,2}
={1,2}
={1,2}
{2,3,4}={2}
Hence, 
Answer:
A = -y^2 + 18
y = 9 + (81 - x)^(1/2) and y =9 - (18 - x) ^(1/2)
Step-by-step explanation:
Given:
P = 2 ( l + w)
x = length and y = width
P = 2 (x + y)
36/2 = x + y
x + y = 18
x = 18 - y
<u>Area:</u>
A = x * y
A = (18 - y) * y
A = 18y - y^2
Using quadratic formula (<u>solve for y</u>):
y = 9 + (81 - x)^(1/2) and y =9 - (18 - x) ^(1/2)
<em>//Not sure it's right.</em>