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sattari [20]
3 years ago
10

Does anyone know the answer for both of these

Mathematics
1 answer:
ASHA 777 [7]3 years ago
3 0
19 is 13 and 20 is 22
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A plane intersects a triangular prism vertically as shown. Describe the cross-section shown here. A) pentagon B) rectangle C) tr
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52 /72
Stolb23 [73]
52/72

13/18 is your answer. Therefore, C.
8 0
3 years ago
3. The following sets are not equal - An (BUC) and AU(BnC) Construct a universe U and non-empty sets A, B, and C so that the abo
yarga [219]

Answer:

1.U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

2.U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

Step-by-step explanation:

We are given that A\cap (B\cup C) and A\cup (B\cap C)

are different sets

1.We have to construct a universe set U and non empty sets A,B and C so that above set in fact the same

Suppose U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

B\cap C=\phi

B\cup C={2,3,4,5}

A\cap (B\cup C)={2}\cap{2,3,4,5}={2}

A\cup (B\cap C)={2}\cup\phi={2}

Hence, A\cap (B\cup C)=A\cup (B\cap C)

2.We have to construct a universe set U and non empty sets A,B and C so that  above sets are in fact different

Suppose U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

B\cap C=\phi

B\cup C={2,3,4}

A\cup (B\cap C)={1,2}\cup \phi={1,2}

A\cap (B\cup C)={1,2}\cap {2,3,4}={2}

Hence, A\cap (B\cup C)\neq A\cup (B\cap C)

3 0
3 years ago
Please help solve this question. Thanks
Misha Larkins [42]

Answer:

A = -y^2 + 18

y = 9 + (81 - x)^(1/2) and y =9 - (18 - x) ^(1/2)


Step-by-step explanation:

Given:

P = 2 ( l + w)

x = length and y = width

P = 2 (x + y)

36/2 = x + y

x + y = 18

x = 18 - y


<u>Area:</u>

A = x * y

A = (18 - y) * y

A = 18y - y^2

Using quadratic formula (<u>solve for y</u>):

y = 9 + (81 - x)^(1/2) and y =9 - (18 - x) ^(1/2)


<em>//Not sure it's right.</em>


6 0
4 years ago
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