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Harlamova29_29 [7]
3 years ago
13

Find the mean and median for the graph?

Mathematics
2 answers:
Vedmedyk [2.9K]3 years ago
7 0

Step-by-step explanation:

Finding the median

The median is the number that is located in the middle of the set of numbers. First you count the number of X's, which is 26. This means that the median is in between number 13 and 14, which is 2 and 3 in this number set. Then you average the two numbers (\frac{2+3}{2}) to get 2.5.

Finding the mean

The mean is the average of all of the numbers located in the set. First, you add up all of the numbers.

5(0) + 5(1) +3(2) + 2(3) +4(4) + 1(5) + 2(6) + 2(7) + 1(8) + 1(9) = 81

After, you divide by how many numbers there are in the set, which as we found earlier, is 26

\frac{81}{26} = 3.12

netineya [11]3 years ago
4 0

Answer:

so from looking at this we can see there is

0=5

1=5

2=3

3=2

4=4

5=1

6=2

7=2

8=1

9=1

now we have to add them up

5+6+16+5+12+14+8+9=75

and now we have to add up the total plots on the chart

5+5+3+2+4+1+2+2+1+1=26

now we divide

75 divided by 26=2.88461538462

so 2.9 is the mean

now we add up the number from least to greatest

0,0,0,0,0,1,1,1,1,1,2,2,2,4,4,4,4,5,6,6,7,7,8,9

so the medien is 4

Hope This Helps!!!

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Use the SF to multiply the missing information
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A.
5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
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B.
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\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
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\boxed{x=11} \Leftarrow \hbox{the second mistake}

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  |\hbox{add 12 to both sides} \\
x=11
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