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DaniilM [7]
3 years ago
11

Which inequality is true?

Mathematics
1 answer:
seraphim [82]3 years ago
6 0
Please include the inequalities to choose from so that we can answer your question.
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PLS HELP THIS IS VERY URGENT!!!! i really need help on this!! I need to turn this in very soon. i would appreciate your help.
Marysya12 [62]

Answer:

17= 2/3

13,,,a=> (5x+5) (x+3)

Step-by-step explanation:

.........................

Forgive me if wrong

8 0
2 years ago
Suzannah made 7 bows. How many feet of ribbon did she use?
ella [17]

Answer:

420

Step-by-step explanation:

5 0
3 years ago
Thea would like to leave a 15% tip.<br> Her bill was $5.40. How much should<br> she leave?
iogann1982 [59]

Answer:

(5.40/100)*115 = 6.21 - 5.40 = 0.81 cents

Step-by-step explanation:

8 0
3 years ago
What is the true solution to the equation below? In e^in x + in e^in x^2 = 2 in 8
mariarad [96]
To solve the given equation, w need to review some rules:
(1) \ ln \ e = 1 \\ &#10;(2) \ ln \  b^{a} = a*ln \ b \\&#10;(3) \ ln \ a + ln \ b = ln \ (ab) \\&#10;(4) \ ln \ a - ln \ b = ln \  \frac{a}{b}  \\

The given equation is :
ln \  e^{ln \ x} + ln \  e^{ln \  x^{2}} = 2 \ ln \ 8
ln \ x * ln \ e + ln \  x^{2} * ln \ e = 2 \ ln \ 8  ⇒⇒⇒⇒ rule (2)
ln \ x + ln \  x^{2} = ln \  8^{2}  ⇒⇒⇒⇒ rule (1) and rule (2)

ln \ ( x*  x^{2} ) = ln \ 64          ⇒⇒⇒⇒ rule (3)
removing the nature logarithm from both sides

x^{3} = 64 =  4^{3}
∴ x = 4


So, the correct answer is option (2) ⇒⇒⇒⇒ x = 4


5 0
3 years ago
Read 2 more answers
Battery packs in electric go-carts need to last a fairly long time. The run-times (time until it needs to be recharged) of the b
pav-90 [236]

Answer:

The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 2, \sigma = 0.33

What is the minimum level for which the battery pack will be classified as highly sought-after class

At least the 100-10 = 90th percentile, which is the value of X when Z has a pvalue of 0.9. So it is X when Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 2}{0.33}

X - 2 = 0.33*1.28

X = 2.42

The minimum level for which the battery pack will be classified as highly sought-after class is 2.42 hours

4 0
3 years ago
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