Answer:
a) H0: mean of exercise group = mean of non exercise group
Ha: mean of exercise group ≠ mean of non exercise group
b) p value is 0.002
c) see the explanation
d) Null hypothesis is rejected. Ha is true
Explanation:
The complete question is:
An investigator theorizes that people who participate in a regular program of exercise will have levels of systolic blood pressure that are significantly different from that of people who do not participate in a regular program of exercise. To test this idea the investigator randomly assigns 21 subjects to an exercise program for 10 weeks. After ten weeks the mean systolic blood pressure of subjects in the exercise group is 137 and the standard deviation of blood pressure values in exercise group is 10. After ten weeks the mean systolic blood pressure of subjects in the non-exercise group is 127 and the standard deviation of blood pressure values in exercise group is 9.
a) State null and alternate hypothesis
b) Include the critical value of appropriate as part of decision rule to for rejecting the null hypothesis
c) show all of your work in reaching a decision as to whether the investgator should reject the null hypothesis or not.
d) State the conclusion te investigator is entitled ot draw on the basis of results
a) H0: mean of exercise group = mean of non exercise group
Ha: mean of exercise group ≠ mean of non exercise group
b) at 5% significance value, the p vaue is 0.002
t= (x1 — x2) /√ (σ1² / √n1 + σ2² / n2),
x1: mean of exercise group
x2: mean of non exercise group
σ1: standard deviation of exercise group
σ2: standard deviation of non exercise group
N1: sample size of exercise group
N2: sample size of non exercise group
t= 4.948
p value is 0.002
Since p value is less t statistic, null hypothesis is rejected.
Ha is true
