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Cerrena [4.2K]
4 years ago
6

Use the factorization to find the values of x for

Physics
2 answers:
TiliK225 [7]4 years ago
8 0

Answer:

Nah son

Explanation:

olga2289 [7]4 years ago
3 0

Answer(x – 1)(x + 1)(x + 5) = 0

x – 1 = 0, so x = 1

x + 1 = 0, so x = -1

x + 5 = 0, so x =  -5

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A 5 kg rock is raised 28 m above the ground level. What is the change in its potential energy?
marin [14]
Let's assume that ground level is the height 0 meters. The change in potential energy is going to be gravitational potential energy, which is given by PE=mgh.
ΔPE=mgh-mgy
=mg(h-y)
=50(28-0)
=1400 J
3 0
4 years ago
similar to the case in the experiment you use two rubber bands, side to side first, to hold a weight of 3 reference objects. the
Sever21 [200]

Three units deformations observed in these bands.

<h3>What forces do a rubber band encounter?</h3>

Elastic force is the force that permits some materials to regain their former shape after being stretched or crushed. Thus, a stretched rubber band is subject to an elastic force.

The rubber band experiment uses a straightforward rubber band to show entropic force and a refrigeration cycle. The rubber band experiment involves stretching and then releasing a rubber band while measuring its temperature.

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7 0
2 years ago
Which of the following has unbalanced force? Someone help pls
Levart [38]
I think its the car moving to a stop sign
4 0
3 years ago
A 50-V de voltage source was connected in series with a resistor and capacitor. Calculate the current in A to two significant fi
Naddik [55]

Answer:

Current through circuit will be 0.2706\times 10^6A

Explanation:

We have given source voltage v = 50 volt

Resistance R=25Mohm=25\times 10^6ohm

Capacitance C=0.1\mu F=0.1\times 10^{-6}F

Time t = 5 sec

Time constant of RC circuit is given by \tau =RC=25\times 10^6\times 0.1\times 10^{-6}=2.5sec

We know that voltage across capacitor is given by v_c=v_s(1-e^{\frac{-t}{\tau }})

v_c=50(1-e^{\frac{-5}{2.5 }})=43.2332v

So current will be =\frac{v_s-v_c}{R}=\frac{50-43.2332}{25\times 10^{-6}}=0.2706\times 10^6A

So current through circuit will be 0.2706\times 10^6A

4 0
4 years ago
A 2.0-m wire carrying a current of 0.60 A is oriented parallel to a uniform magnetic field of 0.50 T. What is the magnitude of t
konstantin123 [22]

Answer:

The force experienced  is 0.6 N

Explanation:

Given data

length of wire L= 2 m

current in wire I= 0.6 A

magnetic field B= 0.5

The force experienced can be represented as

F= BIL

F= 0.5*0.6*2\\\F= 0.6 N

7 0
3 years ago
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