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Natali5045456 [20]
1 year ago
13

similar to the case in the experiment you use two rubber bands, side to side first, to hold a weight of 3 reference objects. the

n, as in the experiment, the bands are pulled apart in their free ends until they form an angle of 30 degrees with respect to the horizontal. what are the deformations observed in these bands? ...
Physics
1 answer:
Sever21 [200]1 year ago
7 0

Three units deformations observed in these bands.

<h3>What forces do a rubber band encounter?</h3>

Elastic force is the force that permits some materials to regain their former shape after being stretched or crushed. Thus, a stretched rubber band is subject to an elastic force.

The rubber band experiment uses a straightforward rubber band to show entropic force and a refrigeration cycle. The rubber band experiment involves stretching and then releasing a rubber band while measuring its temperature.

Always acting in the opposite direction of motion is friction. This indicates that if friction is there, it cancels out some of the force driving the motion (if the object is being accelerated). This results in a decreased acceleration and a smaller net force.

learn more about Elastic force refer

brainly.com/question/5055063

#SPJ14

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7 0
3 years ago
Consider a projectile launched with an initial velocity of v0 = 120 ft/s, inclined at an angle, θ with the horizontal. Let us as
Natali [406]

Answer:

How to find the maximum height of a projectile?

if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest. ...

if α = 45°, then the equation may be written as: ...

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Explanation:

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3 years ago
What are two ways in which all types of precipitation are alike
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7 0
3 years ago
A homeowner wants to reduce the environmental damage of the energy source used to heat her home.
liberstina [14]

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A single-turn circular loop of wire of radius 45 mm lies in a plane perpendicular to a spatially uniform magnetic field. During
Lina20 [59]

Answer:

Magnitude of induced emf is 0.00635 V

Explanation:

Radius of circular loop r = 45 mm = 0.045 m

Area of circular loop A=\pi r^2

A=3.14\times 0.045^2=0.00635m^2

Magnetic field is increases from 250 mT to 350 mT

Therefore change in magnetic field dB=250-350=100mT

Emf induced is given by

e=-N\frac{d\Phi }{dt}=-NA\frac{dB}{dt}

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Magnitude of induced emf is equal to 0.00635 V

7 0
3 years ago
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