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sesenic [268]
1 year ago
10

A low-luminosity star has a small and narrow ________, whereas a high-luminosity star has a large and wide one.

Physics
1 answer:
vova2212 [387]1 year ago
4 0

A low-luminosity star has a small and narrow ​<u>habitable zone</u>, whereas a high-luminosity star has a large and wide one.

<h3>What is luminosity of a star?</h3>

The radiant power emitted by a light-emitting item over time is measured as luminosity, which is an absolute measure of radiated electromagnetic power (light).

The total quantity of electromagnetic energy released per unit of time by a star, galaxy, or other celestial object is referred to as luminosity in astronomy.

Learn more about low-luminosity star:
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How many laws are named after sir issac newton
Blizzard [7]

Answer:

Three Laws

Newton's Three Laws of Motion. Sir Isaac Newton: The Universal Law of Gravitation. Sir Isaac Newton and the Unification of Physics & Astronomy.

Explanation:

3 0
3 years ago
How do geologists construct the geologic column?​
Luda [366]

Answer:

They do this by joining pieces of different Rock sequences together from different places in the whole world.

Explanation:

Geologic columns are basically an arrangement of rock layers whereby the newest rocks are at the top while the oldest rocks will be at the bottom. Thus, it is like a timescale that's used to find the age of rock formation on the earth around the world.

3 0
3 years ago
Problem 2: A rock is dropped from a cliff. If it falls for 10 seconds, what is its displacement?​
Hatshy [7]

Answer:

100 feet

Explanation:

3 0
3 years ago
an object of mass 4 kg is placed on an inclined plane at an angle of 60. if the object slides down the plane with an acceleratio
balandron [24]

The forces on the  y axis are:

N-mgcos(60)=0   , wich becomes

N=mgcos(60)

Rember that the friction force is always contrary to the motion of an object and its formula is  f=μ * N

The forces in the x axis are:

-f + mgsin(60)= m * a

-μ*mgcos(60) + mgsin(60)=m*a  ,

μ = ( m*a - mgf=μ[sin(60) )/ ( mgcos(90) )


6 0
3 years ago
A converging lens has a focal length of 20 cm. An object 1 cm tall is placed 10 cm from the center of the lens. What is the heig
SCORPION-xisa [38]

Answer: 2 cm

Explanation:

Given , for a converging lens

Focal length : f=20\ cm

Height of object : h=1\ cm

Object distabce from lens : u=-10\ cm

Using lens formula: \dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}, we get

\dfrac{1}{20}=\dfrac{1}{v}+\dfrac{1}{10}, where v = image distance from the lens.

On solving aboive equation , we get

\dfrac{1}{v}=\dfrac{1}{20}-\dfrac{1}{10}=\dfrac{1-2}{20}=\dfrac{-1}{20}\Rightarrow\ v=-20\ cm

Formula of Magnification : m=\dfrac{v}{u}=\dfrac{h'}{h} , where h' is the height of image.

Put value of u, v and h in it , we get

\dfrac{-20}{-10}=\dfrac{h'}{1}\\\\\Rightarrow\ h'=2\ cm

Hence, the height of the image is 2 cm.

3 0
3 years ago
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