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3 years ago

6

Tom has two pieces of wood to build a birdhouse. one piece is 3/4 yard long. The other piece is 4/8 yard long. Tom says both pie

ces of wood are the same length. Explain his error

1 answer:

astra-53 [7]3 years ago

4 0

3/4 in decimal form is 0.75
4/8, when simplified, is 1/2 which is 0.5 in decimal form.

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Daniel [21]

9. 1/18

10. 1/18

<u>Here is how I got my answer for 9:</u>

Step 1: Simply $9/54$ to $1/6$ . Which leaves us with $1/6$ - $1/9$

Step 2: Find the least common denominator, which is 18.

Step 3: Make the denominators the same as the least common denominator. By multiplying $6*3$ and $9*2$ . Which leaves us with $3/18$ - $2/18$ .

Step 4: Subtract 3 and two, giving you your answer: $1/18$

<u>Here is how I got my answer for 10:</u>

Step 1: Simplify $6/12$ to $1/2$ . Which leaves us with $1/2$ - $4/9$

Step 2: Find the least common denominator, which is 18.

Step 3: Make the denominators the same as the least common denominator by multiplying $2*9$ and $9*2$ . Which leaves us with $9/18 - 8/18$ .

Step 4: Subtract 9 and 8, giving you your answer: $1/18$

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3 years ago

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Parallelograms (5x+4). 59

prisoha [69]

Answer:

59 = (5x + 4)

x = 11

Step-by-step explanation:

59 = (5x + 4)

5x + 4 = 59

5x = 59 - 4

5x = 55

x = 55/5

x = 11

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3 years ago

The ratio of boys to girls in a class room is 5 to 7. If there are 30 boys then how many girls are there

Brums [2.3K]

Answer:

The ratio of boys to girls to 5:7

Let the number of boys be 5x

Let the number of girls be 7x

5x = 30

x = 6

Now just plug in 6 for the x in 7x

and number of girls 7 x 6 = 42

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3 years ago

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How do I construct angle XYZ with a measure of 2 times the measure of angle ABC

Serjik [45]

I can’t understand why everyone complicates this question. It can be easily solved by similar triangles.

In this png, we have something to make sure.

∠B=∠DAB
∠
B
=
∠
D
A
B
(Yes, dab)

This also means AD=BD
A
D
=
B
D
.

This is our basic construction of D, which is going to help us.

∠ADC=∠DAB+∠B=2∠B=∠CAB
∠
A
D
C
=
∠
D
A
B
+
∠
B
=
2
∠
B
=
∠
C
A
B

∠CAD=∠CAB−∠DAB=∠B
∠
C
A
D
=
∠
C
A
B
−
∠
D
A
B
=
∠
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These are based on the fact that ∠A=2×∠B
∠
A
=
2
×
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Actually these conditions suffice. Because I am just proving that △ACD∼△BCA
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C
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∼
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Similarity makes us realize the following:

ACBC=ADAB
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C
=
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D
A
B

and

ACBC=CDAC
A
C
B
C
=
C
D
A
C

So

AC×AB=BC×AD
A
C
×
A
B
=
B
C
×
A
D

and

AC2=BC×CD
A
C
2
=
B
C
×
C
D

So

BC2=BC×(BD+CD)=BC×(AD+CD)
B
C
2
=
B
C
×
(
B
D
+
C
D
)
=
B
C
×
(
A
D
+
C
D
)

=AC×AB+AC2
=
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×
A
B
+
A
C
2

Q.E.D.
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Step-by-step explanation:

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