Answer:
C
Step-by-step explanation:
It usually works best to use the polynomial with fewer terms as the multiplier. A row of partial products is written for each term of the multiplier, so the fewer terms will result in fewer rows of partial products.
In order to keep like terms together, it is preferable to allocate a separate column of the multiplication tableau to each power of the operands or product. This means we want to make note of the fact that the cubic multiplicand has a coefficient of 0 for its x^2 term.
The best setup is the one shown in the attachment.
35x – 13 x = x – 1
⇒ 22 x = x - 1
⇒ 22x - x = -1
⇒ 21x = -1
⇒ x = -1/21
Thus,the value of x is -1/21
Pythagorean theorem.
a^2+b^2=c^2
This means that the square of the length of the 2 legs of a right triangle added together = the square of the length of the hypotenuses or diagonal.
If you know 2 of the values in the 3 variables a,b,c what would you do to find the missing variable value?
I will not write the exact answers to this problem. I think you can figure how to write it out yourselves.
first, rewrite 54 as 6•9
next, rewrite 42 as 6•7
then, that gets you 6x^2 -6•7x- 6•9
lastly, factor out the common term (6)
and then you get 6(x^2-7x-9)
<u>please mark as brainliet <3</u>
It should be the first one, or 3x, I’m pretty sure because x is going to be the amount that he has and he has 3 times the amount or something
