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-Dominant- [34]
4 years ago
6

In which situation will screening be used to separate a mixture?

Physics
2 answers:
EleoNora [17]4 years ago
8 0

Hello!


I believe the answer is

A) if the mixture is a solid suspended in a gas

mr_godi [17]4 years ago
5 0

Answer: Option (A) is the correct answer.

Explanation:

When granular solids are separated out according to their size then this process of separation is known as screening.

So, when a solid substance dissolves in a liquid then its molecules will dissociate into ions. Therefore, its particles cannot be separated out by screening.

Therefore, when solid particles are suspended in a gas then they can be separated out easily through the process of screening.

Thus, we can conclude that in a situation where the mixture is a solid suspended in a gas then screening be used to separate a mixture.

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A Ferris wheel turns at a constant 150.0 revolutions per hour. (a) Express this rate of rotation in units of radians per second.
RUDIKE [14]

Answer:

(a) 0.261 rad/s

(b) 1007.72 m

Explanation:

The angular velocity of the Ferris wheel is 150.0 revolutions per hour.

(a) To calculate the angular velocity of the wheel in units of radians per second, you take into account the following equivalence:

1 hour = 3600 seconds

1 revolution = 2π radians

You use the previous conversion factors:

150.0\ \frac{rev}{h}*\frac{2\pi \ rad}{1\ rev}*\frac{1\ h}{3600\ s}=0.261\frac{rad}{s}

In units of radians per seconds the wheel turns at 0.261 rad/s

(b) To find the arc length described by the wheel, you first calculate the angle described by the  wheel in the time t, by using the following formula:

\theta=\omega t     (1)

ω: angular velocity = 0.261 rad/s

t: time = 4.95 min

You first convert the time to units of seconds

4.95min*\frac{60s}{1min}=297s

Next, you replace the values of the parameters in the equation (1):

\theta=(0.261\frac{rad}{s})(297s)=77.51rad

Next, you use the following formula for the arc length:

s=r\theta     (2)

r: radius of the wheel = 13.0 m

You replace the values of the parameters in the equation (2):

s=(13.0m)(77.51rad)=1007.72m

The arc length described by the wheel is 1007.72m

4 0
4 years ago
In which situation is the speed of the car constant while its velocity is changing?
Sati [7]

Answer:

B, the car travels around a circular track at 30 m.

Explanation:

7 0
2 years ago
An object is thrown with a horizontal velocity of 20 m/s from a cliff that is 125 m above level ground. If air resistance is neg
Serjik [45]

Given that,

Horizontal velocity of the object, v = 20 m/s

Height of the cliff, h = 125 m

We need to find the time that it takes the object to fall to the ground from the cliff is most nearly. It can be calculated using second equation of motion. Let us consider that the initial speed of the object is 0. So,

h=ut+\dfrac{1}{2}at^2

Here, a = g and u = 0

h=\dfrac{1}{2}at^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 125}{10}} \\\\t=5\ s

So, the object will take 5 seconds to fall to the ground from the cliff.

5 0
3 years ago
how much kinetic energy is produced when an object having mass of 50gm throwing with velocity 80m/s?​
Jlenok [28]

Answer:

KE = 160 J

Explanation:

KE = 1/2mv²

mass= 50gm = 0.05kg

velocity = 80

KE = 1/2 x 0.05 x 80²

= 1/2 x 0.05 x 6400

= 160

4 0
3 years ago
Read 2 more answers
42,43 and 44 please
Mariana [72]
42) The sailboat travels east with velocity v_e=30 mph, while the current moves south with speed v_s=30 mph. Since the two velocities are perpendicular to each other, he resultant velocity will be given by the Pytagorean theorem:
v= \sqrt{v_e^2+v_s^2}= \sqrt{(30)^2+(30)^2}=42 mph
and the direction is in between the two original directions, therefore south-east. So, the correct answer is
D) 42 mph southeast

43) Since the light moves by uniform motion, we can calculate the distance corresponding to one light year by using the basic relationship between velocity, space and time. In fact, we know the velocity:
v=300,000,000 m/s=3 \cdot 10^8 m/s
and the time is one year, corresponding to:
t=32,000,000 s=3.2 \cdot 10^7 s
therefore, the distance corresponding to one light year is:
S=vt=(3\cdot 10^8 m/s)(3.2 \cdot 10^7 s)=9.6 \cdot 10^{15}m
Therefore, the correct answer is D.

44) For the purpose of the problem, we can assume that the light travels instantaneously from the flash to us (because the distances involved are very small), so the time between the flash and the thunder corresponds to the time it took for the sound to travel to us.
The speed of sound is
v=1100 ft/s=750 mph=335 m/s
And since the time between the flash and the thunder is t=3 s, the distance is
S=vt=(335 m/s)(3 s)=1005 m=0.62 miles
Therefore, the correct answer is A) 3/5 mile.
6 0
3 years ago
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