Help me again please im stuck
2 answers:
You might be interested in
We know that
see the attached figure to better understand the problem
sin x°=opposite ÷ <span>hypotenuse
cos x</span>°=adjacent ÷ hypotenuse
cosec x°=1/ sin x°-------> hypotenuse ÷ opposite
sec x°=1/ cos x°-------> hypotenuse ÷ adjacent
therefore
case A) <span>sec x° = opposite ÷ adjacent------------> is not correct
case B) </span>cosec x° = opposite ÷ adjacent ------------> is not correct
case C) cosec x° = hypotenuse ÷ opposite ------------> is correct
case D) sec x° = adjacent ÷ hypotenuse------------> is not correct
the answer is
the equation cosec x° = hypotenuse ÷ opposite is correct
see the attached figure to better understand the problem
sin x°=opposite ÷ <span>hypotenuse
cos x</span>°=adjacent ÷ hypotenuse
cosec x°=1/ sin x°-------> hypotenuse ÷ opposite
sec x°=1/ cos x°-------> hypotenuse ÷ adjacent
therefore
case A) <span>sec x° = opposite ÷ adjacent------------> is not correct
case B) </span>cosec x° = opposite ÷ adjacent ------------> is not correct
case C) cosec x° = hypotenuse ÷ opposite ------------> is correct
case D) sec x° = adjacent ÷ hypotenuse------------> is not correct
the answer is
the equation cosec x° = hypotenuse ÷ opposite is correct