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7nadin3 [17]
3 years ago
6

Can someone help me with this whole page? i can't seem to figure it out. Is physics homework

Physics
1 answer:
Roman55 [17]3 years ago
7 0
Go on khan academy they help you with all of this stuff and you will know more
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What is the
Len [333]

Answer:

d=5\ g/cm^3

Explanation:

Given that,

Mass of the object, m = 100 grams

Volume of the object, V = 20 cm³

We need to find the density of the object. We know that, density is equal to mass per unit volume. So,

d=\dfrac{m}{V}\\\\d=\dfrac{100\ g}{20\ cm^3}\\\\d=5\ g/cm^3

So, the density of the object is equal to 5\ g/cm^3.

6 0
3 years ago
Find A and effective resistance.<br> (Ill give Brainliest if you provide explaination)
Alex777 [14]

Answer:

A = 2.4 A

R_{eq}  = 5 \ \Omega

Explanation:

The voltage in the circuit, V = 12 V

The given circuit shows four resistors with R₁ and R₂ arranged in series with both in parallel to R₃ and R₄ which are is series to each other

R₁ = 4 Ω

R₂ = 6 Ω

R₄ = 5 Ω

The voltage across R₃ = 6 V

Voltage across parallel resistors are equal, therefore;

The total voltage across R₃ and R₄ = 12 V

The total voltage across R₁ and R₂ = 12 V

The voltage across R₃ + The voltage across R₄ = 12 V

∴ The voltage across R₄ = 12 V - 6 V = 6 V

The current flowing through  R₄ = 6V/(5 Ω) = 1.2 A

The current flowing through R₃ = The current flowing through R₄ = 1.2 A

The resistor, R₃ = 6 V/1.2 A = 5 Ω

Therefore, we have;

The sum of resistors in series are R₁ + R₂ and R₃ + R₄, which gives;

R_{series \, 1} = R₁ + R₂ = 4 Ω + 6 Ω = 10 Ω

R_{series \, 2} = R₃ + R₄ = 5 Ω + 5 Ω = 10 Ω

The sum of the resistors in parallel is given as follows;

\dfrac{1}{R_{eq}}  = \dfrac{1}{R_{series \, 1}} + \dfrac{1}{R_{series \, 2}} = \dfrac{R_{series \, 2} + R_{series \, 1}}{R_{series \, 1} \times R_{series \, 2}}

Therefore;

R_{eq} =  \dfrac{R_{series \, 1} \times  R_{series \, 2}}{R_{series \, 1} + R_{series \, 2}}

Therefore;

R_{eq} =  \dfrac{10\times  10}{10 + 10} \ \Omega = 5 \ \Omega

R_{eq}  = 5 \ \Omega

The value of the current, <em>A</em>, in the circuit, I = V/R_{eq}

A = I = 12 V/(5 Ω) = 2.4 A

A = 2.4 A

3 0
3 years ago
Planets in our solar system do not revolve around the sun in perfect circles. Their orbits are more like ovals that scientists d
galben [10]
Planets in our solar system do not revolve around the sun in perfect circles. Their orbits are more like ovals that scientists describe as elliptical. It is one of Kepler's laws. The sun is the focus of all the planets. The correct answer is D.
7 0
4 years ago
A force of 48 newtons is required to start a 5.0 kg box moving across a horizontal concrete floor. What is the coefficient of st
Soloha48 [4]

1) The coefficient of static friction is 0.980

2) The coefficient of kinetic friction is 0.908

Explanation:

1)

In the first situation, the box is still at rest. There are two forces acting on the box:

- The force of push, F, forward

- The force of static friction, F_f

Since the box is in equilibrium we have

F_f = F (1)

The value of frictional force changes from zero to a maximum value which is given by:

F_f = \mu_s mg (2)

where

\mu_s is the coefficient of static friction

m is the mass of the box

g is the acceleration of gravity

So, if the force F needed to put the box in motion is 48 N, it means that this is also the maximum value of the force of friction. So, we can combine eq.(1) and (2) to find the coefficient of static friction:

\mu_s = \frac{F}{mg}

where:

F = 48 N

m = 5.0 kg

g=9.8 m/s^2

Substituting,

\mu_s = \frac{48}{(5.0)(9.8)}=0.980

2)

In this second situation, the object is already in motion, so the equation of motion is:

F-F_f = ma

where

F = 48 N is the force applied forward

a = 0.70 m/s^2 is the acceleration of the box

F_f = \mu_k mg is the force of kinetic friction, where

\mu_k is the coefficient of kinetic friction

We can therefore rearrange the equation to find the coefficient:

F-\mu_k mg = ma\\\mu_k mg = F-ma\\\mu_k = \frac{F-ma}{mg}=\frac{48-(5.0)(0.70)}{(5.0)(9.8)}=0.908

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

7 0
3 years ago
Which are advantages of reflecting telescopes? Check all that apply.
Mashcka [7]

On e2020 the answers are:

1. There is no rainbow-like halo around the image.

2. Reflecting telescopes can be made very large.

4. Only the reflecting side of the primary mirror needs to be perfectly shaped and smooth.

I hope that helps!!

3 0
3 years ago
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